4 g of Helium = 1 mole.So, 56 g of helium = 14 moles
If you are talking about dinitrogen (N2), then this is the answers.
? mol= 42 g * 1 mol/28.02 g = 1.50 moles
The answer is 2,5 moles.
4
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
0.250 mol
8,4 liters of nitrous oxide at STP contain 2,65 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
0.25 moles
0.67 mol
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
3.058
0.250 mol
The amount of oxygen is 0,067 moles.
Ideal gas law.PV = nRT(1.00 atmosphere)(30 L) = n(0.08206 L*atm/mol*K)(298.15 K)n(moles O2) = 30/24.466= 1.2 moles oxygen gas================
A cubic decimeter is a liter, so we're talking 50L of oxygen gas at STP. 1mol of any gas at STP occupies 22.4L of space, so 50/22.4 = about 2.2mol of oxygen.
No. of moles = mass/relitive molecular mass in this case = 10/16 = 0.625 so that's 0.625 of a mole and a mole of anything contains 6.022 x 1023 atoms = 3.76 x 1023 atoms in 10g of oxygen.
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.