I may be wrong, but I think that the Lewis dot structure of CH4O consists of the Carbon atom being bonded to three of the Hydrogen atoms, and the Oxygen atom. The Oxygen atom then is bonded to the remaining Hydrogen (as it is an OH group) and the electrons to fill O's octet are then drawn in.
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H3 - C - O - H two lone pairs on oxygen
three hydrogen on carbon
A phosphorus atom has five electrons in its Lewis Dot Structure. Phosphorus has five valence electrons in its outer shell, so each electron is represented as a dot in the Lewis Dot Structure diagram.
Lithium: Li has 1 valence electron, so its Lewis dot diagram is Li: . Bromine: Br has 7 valence electrons, so its Lewis dot diagram is :Br:. Carbon: C has 4 valence electrons, so its Lewis dot diagram is :C:. Hydrogen: H has 1 valence electron, so its Lewis dot diagram is H: . Silver: Ag has 1 valence electron, so its Lewis dot diagram is Ag: . Oxygen: O has 6 valence electrons, so its Lewis dot diagram is :O:. Iron: Fe has 2 valence electrons, so its Lewis dot diagram is :Fe:. Potassium: K has 1 valence electron, so its Lewis dot diagram is K: . Oxygine: I'm not familiar with an element called "oxygine". It may be a misspelling of oxygen. If so, refer to oxygen's Lewis dot diagram above.
The Lewis symbol for phosphorus should show 5 dots. Each dot represents a valence electron of the phosphorus atom.
The Lewis dot diagram for calcium (Ca) has 2 dots on the symbol "Ca" representing its two valence electrons. The Lewis dot diagram for fluorine (F) has 7 dots surrounding the symbol "F," representing its seven valence electrons.
Sodium and neon are both represented by Lewis dot diagrams, which show the valence electrons of the atoms. Oxygen is often represented by a Lewis structure diagram, which shows the arrangement of atoms and the sharing of electrons in a molecule.