Write a program in 8086 assembly language to generate the factorial of given number?

Answer 1

Aim: - To write an assembly language program to find sum of cubes of given 'n' numbers.

1

2

3

4

5

6

7

8

9

MOV CL, NUM

MOV SUM, 00

L1: MOV AL, CL

MUL AL

MUL CL

ADD AL, SUM

MOV SUM, AL

LOOP L1

END

Result: Sum of cubes of first 'n' natural numbers is obtained.

Answer 2

TITLE Calculating a Factorial (Fact.asm)

; This program uses recursion to calculate the

; factorial of an integer.

; Last update: 06/01/2006

INCLUDE Irvine32.inc

.code

main PROC

push 12 ; calculate 12 factorial

call Factorial ; calculate factorial (eax)

ReturnMain:

call WriteDec ; display it

call Crlf

exit

main ENDP

Factorial PROC

push ebp

mov ebp,esp

mov eax,[ebp+8] ; get n

cmp eax,0 ; n < 0?

ja L1 ; yes: continue

mov eax,1 ; no: return 1

jmp L2

L1: dec eax

push eax ; Factorial(n-1)

call Factorial

; Instructions from this point on execute when each

; recursive call returns.

ReturnFact:

mov ebx,[ebp+8] ; get n

mul ebx ; ax = ax * bx

L2: pop ebp ; return EAX

ret 4 ; clean up stack

Factorial ENDP

END main

Answer 3

MOV AH,1 ; for taking input from the user

INT 21H ;interrupt

XOR AH, AH ;used xor to make ah=0

SUB AX,30H ; ascii adjustment

MOV CX,AX ; copy the value of ax into cx

MOV AX,1 ;make ax=1

GO:

MUL CX ;multiply the content of AL with CH

LOOP GO ; loop will decrement the value of CX by one