Can you Write a program in c plus plus to display the multiplication table?

Answer 1

void printTable() {

// pre-print column headers
printf(" ");
int c;
for (c = 0; c <= 10; ++c) {
printf("%4d", c);

}
printf("\n");

printf(" ");
for (c = 0; c <= 10; ++c) {
printf(" -");

}
printf("\n");

// calculations
int r;
for (r = 0; r <= 10; ++r) {

// row headers
printf("%2d|", r);

// calculation for the current row
for (c = 0; c <= 10; ++c) {

printf("%4d", (r * c));

}
printf("\n");

}

}

Answer 2

#include<stdio.h>

#include<conio.h>

void main()

{

int n,p,i;

printf("\n enter the noof which u want to see the table");

scanf("%d",&n);

for(i=1;i<=10;i++)

{

p=n*i;

printf("\n%d *%d=%d",n,i,p);

}

getch();

}

Answer 3

#include

#include

main()

{

int s,k,mul;

clrscr();

for(s=0;s<=12;s++)

{

for(k=0;k<=10;k++)

mul=s*k;

}

printf("the table for 1 to 12 no. is%d",mul);

getch();

return 0;

}

Answer 4

#include<iostream>

#include<iomanip>

int main()

{

using namespace std;

int r,c;

cout<<"Multiplication Table\n\n"<<setw(4)<<"";

for(c=1; c<=12; ++c )

cout<<setw(4)<<c;

cout<<endl;

for(r=1; r<=12; ++r )

{

cout<<setw(4)<<r;

for(c=1; c<=12; ++c )

cout<<setw(4)<<r*c;

cout<<endl;

}

cout<<endl;

return(0);

}

Answer 5

#include<iostream>

#include<iomanip>

using std::cout; // std out

using std::endl; // newline and flush

using std::setw; // set width

int main()

{

// the largest value is 144 (12*12) which has 3 digits

// thus each value requires a minimum width of 4 columns

unsigned width=4;

// loop control variables

unsigned row, column;

// display the table title

cout<<"Multiplication Table\n"<<endl;

// display the column header

cout<<setw(width)<<'|';

for (column=1; column<=12; ++column)

cout<<setw(width)<<column;

cout<<endl;

// underline the column header

for (column=0; column<=12; ++column)

cout<<setw(width)<<"----";

cout<<endl;

// loop through each row

for (row=1; row<=12; ++row)

{

// display the row header

cout<<setw(width-1)<<row<<'|';

// loop through each column and

// display the row and column products

for (column=1; column<=12; ++column)

cout<<setw(width)<<row*column;

cout<<endl;

}

cout<<endl;

}

Output:

Multiplication Table

| 1 2 3 4 5 6 7 8 9 10 11 12

----------------------------------------------------

1| 1 2 3 4 5 6 7 8 9 10 11 12

2| 2 4 6 8 10 12 14 16 18 20 22 24

3| 3 6 9 12 15 18 21 24 27 30 33 36

4| 4 8 12 16 20 24 28 32 36 40 44 48

5| 5 10 15 20 25 30 35 40 45 50 55 60

6| 6 12 18 24 30 36 42 48 54 60 66 72

7| 7 14 21 28 35 42 49 56 63 70 77 84

8| 8 16 24 32 40 48 56 64 72 80 88 96

9| 9 18 27 36 45 54 63 72 81 90 99 108

10| 10 20 30 40 50 60 70 80 90 100 110 120

11| 11 22 33 44 55 66 77 88 99 110 121 132

12| 12 24 36 48 60 72 84 96 108 120 132 144

Answer 6

#include<stdio.h>int main (void) {

int row, column;

for (column=1; column<=12; ++column) {

printf ("\t%d", column);

}

printf ("\n");

for (row=1; row<=12; ++row ) {

printf ("%d", row);

for (column=1; column<=12; ++column) {

printf ("%d\t", row*column);

}

printf ("\n");

}

return 0;

}

Answer 7

There are many ways to solve this problem. You can use different algorithms to fix this. But you may want to try this algorithm. It works for me.

1. Declare and define the main function.
   
2. Declare 4 variables. The first variable is for the number of digits to be multiplied, the second variable is the total of the two numbers multiplied. The third and fourth variable is used as a loop counter and the multipliers and multiplicands in our multiplication.
3. Ask the user to input how many numbers does the multiplication table will include.
4. Since the C console will print data in a linear way, using a for loop, print the columns to be multiplied on the column.
5. After printing the rows, declare another separate for loop. Print the multiplicand value by printing the counter of that for loop.
6. Add a nested for loop. This will serve as the multiplier. Multiply the counter of the first for loop to the counter of the nested for loop. Print the results.

Here is a sample code:

#include

#include

int main (int argc, char *argv[])

{

int numbers = 0;

int total = 0;

int counter = 0, counter2 = 0;

printf ("Type the numbers that will be printed in multiplication table: ");

scanf ("%d", &numbers); // ask user how many numbers to include

printf ("\nMultiplication Table: 1 to %d\n\n", numbers);

for (counter = 1; counter <= numbers; counter++) { // type the number of columns

printf ("\t%d", counter);

}

printf ("\n");

for (counter = 1; counter <= numbers; counter++) {

printf ("\n%d", counter);

for (counter2 = 1; counter2 <= numbers; counter2++) {

total = counter * counter2; // multiply the multiplier times the multiplicand

printf ("\t%d", total); // print the total

}

}

return (0);

} // main

Answer 8

write a c program that prints out the multiplication table of 4 using function

Answer 9

for (unsigned i=1; i!=100; ++i)

std::cout << "2 x " << i << " = " << i*2 << std::endl;

Answer 10

std::cout << "Enter a whole number: ";std::cin >> num;

for (unsigned x=1; x<=12; ++x) std::cout << x*num << ',';

std::cout<<std::endl;