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No. The reciprocal is additive. The formula for the equivalent resistance, in parallel, is 1/R = 1/R1 + 1/R2 + 1/R3... where R is the total equivalent resistance, and R1, etc. are the individual resistances in parallel. Note that the equilalent resistance will be less than any of the individual resistances.

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Q: Is resistance additive in a parallel circuit?

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in a parallel circuit resistance decreases increasing the current.

Yes In parallel circuit , current entering into the circuit will be divided intodifferent paths ( resistances) . Amount of current flow depends upon the magnitude of resistance applied in the circuit. Total current after passing through the circuit will be the sum of all current through each resistance.

Voltage is additive Resistance is additive Current is common

A circuit that has resistances singly, in series, in parallel, or series parallel.

If you connect the SAME resistors in parallel or in series, the series circuit will always have the greater equivalent resistance.

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in a parallel circuit resistance decreases increasing the current.

Yes In parallel circuit , current entering into the circuit will be divided intodifferent paths ( resistances) . Amount of current flow depends upon the magnitude of resistance applied in the circuit. Total current after passing through the circuit will be the sum of all current through each resistance.

Resistances are additive in a series circuit.

Yes. That's what it does.

Voltage is additive Resistance is additive Current is common

Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.

A circuit that has resistances singly, in series, in parallel, or series parallel.

Kirchhoff said so. The paths separate the current when entering the parallel branches according to the resistance of the paths. Then they add back up when the circuits rejoin.

In principle, it is infinite. I have not connected a parallel circuit in ages.

If additional resistance is connected in parallel with a circuit the supply voltage will decrease?

No change in supply voltage as additional resistance is connected in parallel circuit.

Yes. Rt=R1+R2

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