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No. The reciprocal is additive. The formula for the equivalent resistance, in parallel, is 1/R = 1/R1 + 1/R2 + 1/R3... where R is the total equivalent resistance, and R1, etc. are the individual resistances in parallel. Note that the equilalent resistance will be less than any of the individual resistances.

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โˆ™ 2010-09-19 21:55:10
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Q: Is resistance additive in a parallel circuit?
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