Write a program that prompts the user to enter an integer and determines whether it is divisible by 5 and 6 whether it is divisible by 5 or 6 and whether it is divisible by by 5 or 6 but not both?

Answer 1

#! /usr/bin/env ruby

n = gets.to_i

d = 'is not'

d = 'is' if n % 7 == 0

puts 'Your number ' + d + ' divisible by seven.'

For more accurate answer, please define the programming/script language you plan to use..

Answer 2

#include <stdio.h>

#define DIVIDE_5 printf("Divided by 5\n")

#define DIVIDE_6 printf("Divided by 6\n")

#define FALSE 0x00

void main()

{

int number = 0x00;

unsigned char divide_5 = FALSE;

unsigned char divide_6 = FALSE;

printf("Enter the Number:");

scanf("%d", &number);

divide_5 = (number % 5) 0x00 ? DIVIDE_6 : FALSE;

if(!divide_6 && !divide_5 )

printf(" Cannot be divided by 5 or 6\n\n");

}

Answer 3

public class Check5Divisbility {

public String checkDiv(int x){

if(x%5 == 0){

return "Yes"

} else {

return "No"

}

}

}

the above method checkDiv can be used to check if the input number 'x' is divisible by 5 or not. The method will return Yes if the number is divisible and No if it is not divisible

Answer 4

bool isNumberDivisibleByFive(int number)

{

return(!(number % 5));

}

Answer 5

int num = 0;

int sum = 0;

// 105 is the first integer greater than 100 which is evenly divisible by 7

for(int i = 104; i < 200; i+=7) {++num;sum += i;

}

Answer 6

wap to input a number and check whether it is divisible by 7 or no