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Q: What is acceleration of car that moves from speed of 5.0 meters per second to speed of 15 meters per second in 6.0 seconds?

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It is accelerating at 1.2m/s per second.

No, If a car moves around a circular race track with any constant speed, the acceleration is directed towards the centre. So it has a centripetal acceleration. The tangential acceleration would be irrelevant unless the car has an instantaneous tangential velocity of zero. Then the centripetal acceleration is zero. However, this would only exist for that small instant in time.

10-15 seconds

Newton's Law.First law: When viewed in an intertial reference frane, an object either is at rest or moves at a constant velocity , unless acted upon by an external froce .Second law: The acceleration of a body is directly proportional to, and in the same direction as, the net force acting on the body, and inversely proportional to its mass.Third law: When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction to that of the first body.

Newton's Law:First law: When viewed in aninertial reference frame, an object either is at rest or moves at a constant velocity, unless acted upon by an external force.Second law: The acceleration of a body is directly proportional to, and in the same direction as, the net force acting on the body, and inversely proportional to its mass. Thus, F = ma, where F is the net force acting on the object, m is the mass of the object and a is the acceleration of the object.Third law: When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction to that of the first body.

Related questions

Acceleration = (change in speed)/(time for the change) = (15-5)/(6) = 10/6 = 12/3 meters per second2

It is accelerating at 1.2m/s per second.

Acceleration = change in speed per unit of time = (15-0)/10 = 1.5 metres/sec2

Her acceleration is 0.33 meters per second squared.

Yes. When it moves around the Sun, there is circular acceleration, that can be calculated via the formula a = v2 / r. Velocity should be converted to meters / second, radius (of the orbit) to meters - in this case, the result is in meters per second squared.Yes. When it moves around the Sun, there is circular acceleration, that can be calculated via the formula a = v2 / r. Velocity should be converted to meters / second, radius (of the orbit) to meters - in this case, the result is in meters per second squared.Yes. When it moves around the Sun, there is circular acceleration, that can be calculated via the formula a = v2 / r. Velocity should be converted to meters / second, radius (of the orbit) to meters - in this case, the result is in meters per second squared.Yes. When it moves around the Sun, there is circular acceleration, that can be calculated via the formula a = v2 / r. Velocity should be converted to meters / second, radius (of the orbit) to meters - in this case, the result is in meters per second squared.

A rocket that travels 9000 meters in 12.12 seconds moves at 742.5742 meters/second which is approx 1660 mph

20 meters per second

If an object moves 50 meters in 5 seconds, its average speed is 50/5 = 10 meters per second.

2 meters/second or 7 km/h

The unit rate is how far something moves in ONE second. So in this case you divide by 28 (the number of seconds). 12/28=0.4285714285714286 meters a second.

m/s², or meter per squared second. Acceleration is the amount by which speed increases. So if in t=0 a body moves at 5 meters per second, and in t=1 it is moving at 10 meters per second, it is accelerating, and the acceleration rate is 5 meters per second per second. Thus, 5(m/s)/s = 5 m/s²

20

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