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It is actor Stephen Shephered. The guy that plays michael moon in eastenders.

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Q: Who is voice over for new b and q ad?
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Who does the voice over for the new B of A commercials?

The person who does the voice over for the Bank of America ads is Keifer Sutherland. He also does the voice overs for other ads including Nissan & Verizon.


How is a plus b over a minus b equals c plus d over c minus d?

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c


If bd does not equal 0 then a over b plus c over d equals?

If bd ≠ 0, then a/b + c/d (the common denominator is bd) = (a x d)/(b x d) + (c x b)/(d x b) = ad/bd + cb/db = ad/bd + cb/bd = (ad + cb)/ bd


What do you do after cross multiplying when comparing fractions with unlike denominators?

Suppose the two fractions are a/b and c/d ad that b, d > 0. Then cross multiplication gives ad and bc. If ad > bc then a/b > c/d, If ad = bc then a/b = c/d, and If ad < bc then a/b < c/d


What can you use to rewrite a over b equals c over d as ad equals cb?

it is the crossproducts property...right that down now...


If a over b equals c over d then is it possible that a plus b equals c plus d If not then give Mathematical Reason for that?

a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)


Does Voice Over internet enable you to use the internet for phone calls?

Yes it does. VoIP stands for Voice over Internet Protocol, so the name says it all really. The technology uses compressed digital voice packets to transfer sounds from point A to point B over the Internet.


Can you always find another fraction in between ant two fractions why?

Yes. The simple answer is that rational fractions are infinitely dense. A longer proof follows:Suppose you have two fractions a/b and c/d where a, b, c and d are integers and b, d are positive integers.Without loss of generality, assume a/b < c/d.The inequality implies that ad < bc so that bc-ad>0 . . . . . . . . . . . . . . . . . . . (I)Consider (ad + bc)/(2bd)Then (ad+bc)/2bd - a/b = (ad+bc)/2bd - 2ad/2bd = (bc-ad)/2bdBy definition, b and d are positive so bd is positive and by result (I), the numerator is positive.That is to say, (ad+bc)/2bd - a/b > 0 or (ad+bc)/2bd > a/b.Similarly, by considering c/d - (ad+bc)/2bd is can be shown that c/d > (ad+bc)/2bd.Combining these results,a/b < (ad+bc)/2bd < c/d.


What two advantages of using ad ds-integrated dns zones over standard dns zones?

a. All AD DS-integrated DNS zone records are stored in the Active Directory database. b. AD DS-integrated DNS uses the multimaster replication process of AD.


What two advantages of using ad ds integrated dns zones over standard dns zones?

a. All AD DS-integrated DNS zone records are stored in the Active Directory database. b. AD DS-integrated DNS uses the multimaster replication process of AD.


Who is B-Dawg?

Skyler Gisondo does the voice of b-dawg


Is it really over?

yes honey it really is over now get over it and find a new mate b****