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Reactance is -1/2 pi F C so a 25 uF capacitor at 400 Hz would have a reactance of about -15.9 ohms. The negative sign indicates that capacitive reactance is leading, with current leading voltage.

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I would take issue with the previous answer that capacitive reactance is expressed as a negative value, or that it is 'leading'. Reactance is not a vector quantity, so it neither leads nor lags anything. In a (theoretically) purely capacitive circuit, it is the load current that leads the supply voltage. However, when using complex notation, capacitive reactance is expressed as -j 15.9 ohms, where 'j' is called an 'operator' -but even this does not mean that the reactance is 'leading', as it defines reactance in terms of a current phasor -in other words, the '-j' refers to the relative position of current to voltage, not reactance to impedance.

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Q: What is the reactance of a 25 uf capacitor when the applied frequency is 400 hz?
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Related questions

How much voltage does a resistor drop in a circuit with 20 volts 1kHz capacitor at 0.47 milli Farads and a 400 ohm resistor?

The reactance of the capacitor is 0.339 ohms, therefore the total impedance is sqrt(4002+0.3392) = 400.0001 ohms. So the resistor drops very nearly 20 volts, very slightly less.


How many current drawn in 400 kvar capacitor bank?

It depends upon at how much voltage level 400 kvar capacitor bank is used.


If a coil has 100 microhenries inductance at 400 hertz what is it's reactance?

The reactance of an inductor is calculated as Xl = 2πfL, where Xl is the inductive reactance, f is the frequency, and L is the inductance. Substituting the given values of 100 microhenries for inductance and 400 Hz for frequency into the formula gives Xl = 2 * π * 400 * 100 * 10^-6 which equals approximately 251.3 ohms.


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