ch3cooc2h5
Acetic acid when reacts with an alcohol forms an ester, CH3COOH + C2H5OH = CH3COOC2H5 + H2O
It is an ester. Ethyl alcohol + acetic acid ---> ethyl acetate C2H5OH + CH3COOH ----> CH3COOC2H5
c2h5oh+ch3cooh-ch3cooc2h5+h2o ethanol+ethanoic acid-ethyle ethonate + water
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ch3cooc2h5
Acetic acid when reacts with an alcohol forms an ester, CH3COOH + C2H5OH = CH3COOC2H5 + H2O
It is an ester. Ethyl alcohol + acetic acid ---> ethyl acetate C2H5OH + CH3COOH ----> CH3COOC2H5
c2h5oh+ch3cooh-ch3cooc2h5+h2o ethanol+ethanoic acid-ethyle ethonate + water
Ester will form having molecular formula CH3COOC2H5
The structural formula is CH3COOCH2CH3
What we have here is a structural formula. So first, let's simplify it down to a chemical formula, which gives us C3H8O2. There are no common denominators shared by the numbers of all three elements present, so it cannot be simplified any further, so the empirical formula is C3H8O2.
Sodium Acetate Can be fond in 2 forms. Either anhydrous or trihydrate. Oxidation reaction with anhydrous form is easier than trihydrate form. First form has reaction similar to that of Oxidation of Acetic Acid. Trihydrate form is a bit more complex and I'm still loking into it
A dehydration reaction of a carboxylic acid and an alcohol using an acid catalyst:R1COOH + R2OH --> R1CO-OR2 + H-OH (water is driven away to drive the reaction)This is done by using the alcohol's oxygen as a nucleophile and forming a tetrahedral intermediate. Most importantly--the -OH group of the carboxylic acid must become a better leaving group by protonating it to become -OH2+ group.Esters can also form using base as a catalyst.R1COO-+ R2OH --> R1CO-OR2 +-OH
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