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What is the molecular formula of a compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole?

Updated: 8/9/2023

Wiki User

∙ 5y ago

Best Answer

Look at your atomic masses for phosphorus and oxygen. Set up 2.5/31 and 3.23/16. This makes 0.08 and 0.2. Now consider 0.08/0.2 to equal 0.4. So, your ratio of P to O is 0.4, which is 4/10. So, your formula, which reflects that ratio, is P4O10. That's tetraphosphorus decoxide, a molecular solid used in match-heads.

Wiki User

∙ 9y ago

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Wiki User

∙ 5y ago

This compound may be dioxane - C4H8O2.

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Wiki User

∙ 14y ago

the answer is: P4O10

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Wiki User

∙ 10y ago

C6h12o6

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Q: What is the molecular formula of a compound with an empirical formula of C2OH4 and a molar mass of 88 grams per mole?

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What is the molecular formula of a compound that has an empirical formula of c2oh4 and a molar mass of 88 grams per mole?

C4O2H8

What is C2OH4?

Believe this to be Carbon hydroxide

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