approximately 10-14
At -25 Celsius, water will be a solid. Converting from Celsius to Fahrenheit, -25 C is -13 F.
KBr, because it is an ionic compound, and many ionic compounds dissociate in water.
The state of water at -25 C is solid. Water freezes at 0 degrees Celsius.
Silver chloride is ionic but has a low solubility in water. from wikipedia 520 μg/100 g at 50 °C
KMNO4 is ionic and so can be considered polar.
At -25 Celsius, water will be a solid. Converting from Celsius to Fahrenheit, -25 C is -13 F.
Carbon (C) doesn't react with water.
12.28 at 25°C 12.28 at 25°C in water
Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C
KBr, because it is an ionic compound, and many ionic compounds dissociate in water.
The state of water at -25 C is solid. Water freezes at 0 degrees Celsius.
At 25 degrees C the density of water is 1.0 g/mL. If the temperature of the water goes above 25 degrees C the density will drop. If the temperature of the water goes below 25 degrees C the density will rise.
Silver chloride is ionic but has a low solubility in water. from wikipedia 520 μg/100 g at 50 °C
In fresh water, ~1500 m/s at 25°C
KMNO4 is ionic and so can be considered polar.
Covalent bonds: C-H and C-C Polar covalent bonds: C-O and O-H Ionic bonds: None
The specific heat capacity of water between 25 C and 100 C is 4.1813 J / (g*K). Beyond 100 C, the heat capacity of water is 2.080 J / (g*K) So, it take 4.1813 joules of energy to heat 1 gram of water 1 degree Celsius (Kelvin). Therefore, in order to heat 22 g of water from 25 C to 100 C (75 C), it would require: 4.1813 * 22 * 75 = 6899.145 J And, to heat 22 g of steam from 100 C to 125 C (25 C), it would require: 2.080 * 22 * 25 = 1144 J The combined amount of energy required would be: 6899.145 + 1144 = 8043.145 J