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approximately 10-14

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Q: What is ionic product of water at 25 C?
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What will be state of water at -25 C?

At -25 Celsius, water will be a solid. Converting from Celsius to Fahrenheit, -25 C is -13 F.


What is the ionic equation for the reaction between carbon and water?

Carbon (C) doesn't react with water.


What is the pKa of glucose?

12.28 at 25°C 12.28 at 25°C in water


How is Kw valid?

Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C


Which will dissociate when placed in water a. CH3OH b. HCl c. KBr d. HClO4?

KBr, because it is an ionic compound, and many ionic compounds dissociate in water.


What will be the state oh water at 25 C?

The state of water at -25 C is solid. Water freezes at 0 degrees Celsius.


What is the density of PURE water in its liquid state?

At 25 degrees C the density of water is 1.0 g/mL. If the temperature of the water goes above 25 degrees C the density will drop. If the temperature of the water goes below 25 degrees C the density will rise.


Is Ag-Cl ionic or molecular?

Silver chloride is ionic but has a low solubility in water. from wikipedia 520 μg/100 g at 50 °C


What is the velocity of sound in water?

In fresh water, ~1500 m/s at 25°C


Is KMnO4 polar?

KMNO4 is ionic and so can be considered polar.


Is C2H5OH a ionic or convalent bond?

Covalent bonds: C-H and C-C Polar covalent bonds: C-O and O-H Ionic bonds: None


How many joules are required to heat 22 g of water from 25 degrees C to steam at 125 degrees C?

The specific heat capacity of water between 25 C and 100 C is 4.1813 J / (g*K). Beyond 100 C, the heat capacity of water is 2.080 J / (g*K) So, it take 4.1813 joules of energy to heat 1 gram of water 1 degree Celsius (Kelvin). Therefore, in order to heat 22 g of water from 25 C to 100 C (75 C), it would require: 4.1813 * 22 * 75 = 6899.145 J And, to heat 22 g of steam from 100 C to 125 C (25 C), it would require: 2.080 * 22 * 25 = 1144 J The combined amount of energy required would be: 6899.145 + 1144 = 8043.145 J