0
CQ10 or co-enzyme 10 has been highly touted as a supplement to increase energy and enhance the immune system. Those suffering from Congestive heart failure and high blood pressure are supplementing their diets for CQ10's benefits.
Wiki User
โ 9y ago
Add your answer:
Earn +20 pts
If sand has a specific-heat capacity of 835 jkgC then how much energy must be added to a 2 kilogram pile of it to increase its temperature from 40 C to 50 C?
Q = m c ΔT Q = energy m = 2 kg c = 835 J / (kg C) ΔT = 10 C Q = 2 kg * 835 J / (kg C) * 10 C Q = 16700 J
What are the notes for jingle bell for alt sax?
Q= Quarter note, H= Half note, FL= Full note, |= end of bar 4 E-Q E-Q E-H | E-Q E-Q E-H | E-Q G-Q C-Q D-Q | E-FL | F-Q F-Q F-Q F-Q | F-Q E-Q E-H 4------------------------------------------------------------------------------------------------------- E-Q D-Q D-Q E-Q | D-H G-H | E-Q E-Q E-H | E-Q E-Q E-H | E-Q G-Q C-Q D-Q | E-FL | -------------------------------------------------------------------------------------------------------- F-Q F-Q F-Q F-Q | F-Q E-Q E-H | G-Q G-Q F-Q D-Q | C-FL |
What is a algebraic expression for 10 plus q?
It is simply: 10+q
Q squared plus 20 q plus c?
I'm not exactly sure what you mean by this, but if you'd like to know how to do this in C here: q ^ 2 + 20 q + c
There are two Q's in a C What does Q and C stand for?
two quavers in a crotchet
How many KJ is required to heat 10 kilogams of water from 10 degrees C 110 degrees c?
q(Joules) = mass * specific heat * change in temperature ( 10 kg = 10,000 grams )q = (10,000 g)(4.180 J/gC)(110o C - 10o C)= 4180000 Joules (1 kj/1000 J)= 4.2 X 103 kilojoules================
A positive test charge of 5.00 E-5 C is placed in an electric field The force on it is 0.751 N The magnitude of the electric field at the location of the test charge is what?
We have to use F = E q Given F = 0.751 N, q = 5*10-5 C So required E = F /q = 0.751/5*10-5 Electric field at the location E = 15020 N C-1 or V m-1
Q m c T?
That's not a question. Q = (m)(c)(deltaT)
What is the distance between a -2.00 mC charge and a -3.00 mC charge if their potential energy is 0.491 J?
Electric potential energy (U) of two point charges q and Q, is k*q*Q/r. the constant k is equal to 9 x 10^9 Newton meter^2 per Coulomb^2. So 0.491 N*m = (-2 x 10^-3 C)(-3 x 10^-3 C)*(9 x 10^9 N m^2 / C^2) / r. Solving gives r = 109979 meters.
What are the release dates for Pensacola Wings of Gold - 1997 C-Q- 2-20?
Pensacola Wings of Gold - 1997 C-Q- 2-20 was released on: USA: 3 May 1999 Germany: 10 October 1999
A parallel plate capacitor with each plate having area of 1m2 and you separate the plates by 2 ยตm what is the value of the capacitance how much charge will the capacitor store connected to a 10V batt?
Find capacitance: C = Er * Eo * A / d C = (1.0005898) * (8.854×10−12)* (1meter squared) / 2 x 10^-6 C = 4.42 micro farads To determine charge Q: Q = C*V = 4.42 x 10^-6 * 10 volts = 4.42 x 10^-5 coulumbs.
How many electrons should be removed from each similar spheres each of 10 grams so that electrostatic repulsion be balanced by gravitational force?
Data m1=m2=m=10g=10/1000=0.01Kg q1=q2=q n=? Solution As given in question, electrostatic force of repulsion is balanced by gravitational force. F_e=F_g k (q_1 q_2)/r^2 =G (m_1 m_2)/r^2 kqq=Gmm kq^2=Gm^2 q^2=(Gm^2)/k q^2=(6.67รใ10ใ^(-11)รใ0.01ใ^2)/(9รใ10ใ^9 ) q^2=74.11รใ10ใ^(-26) C^2 Square root on both sides โ(q^2 )=โ(74.11รใ10ใ^(-26) C^2 ) q=8.606รใ10ใ^(-13) C Number electrons q=ne q/e=n (8.608รใ10ใ^(-13))/(1.6รใ10ใ^(-19) )=n 5.38รใ10ใ^6=n
