t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
10 gallons..
132 gallons 16 : 84 of 60 gallons = 9.6 : 50.4 gallons 80 : 20 of 132 gallons = 105.6 : 26.4 gallons added = 115.2 : 76.8 gallons = 1.5:1 ( 60:40)
50 bajillion
No, sand covers about 20 percent pf deserts.
You will never get it there. However much 50% you have, any amount of 20% in the mix will reduce the total below 50%. So, throw away the 20% and just use the 50% on its own.
50 percent of (100/20) = 50 percent of 5 = 2.5 (50 percent of 100) / 20 = (50 / 20) = 2.5 as well
20% of 17 gallons= 20% * 17= 0.2 * 17= 3.4 gallons
50 gallons @ 3% must be added.
t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
20% of 190 gallons of water= 20% * 190= 0.2 * 190= 38 gallons of water
20 is what percent of 50= 20 / 50= 0.4Converting decimal to a percentage:0.4 * 100 = 40%
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
20 / 0.5 = 40 Therefore, 20 is 50 percent of 40.
50 percent of 20 cents = 10 cents
50 Pints = 6.25 Gallons
10 gallons..