Boron
Given : Atomic mass of B = 10.01 amu , % = 19.9 let it be A Atomic mass of B = 11.01 amu , % = 80.1 Solution : A and B are approximately in the ratio 1:4. Isotopic mass = [(proportion of A X at. mass of A) + (proportion of B X at. mass of B)] / 4 = [(1 X 10.01) + (4 X 11.01)] / 4 = (10.01 + 44.04) / 4 = 54.05 / 4 Isotopic atomic mass = 13.512 amu ---- Therefore, isotopic atomic mass of B is = 13.512 amu.
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
Atomic mass is simply the sum of the number of protons and the number of neutrons. If an atom has "A" protons and "B" neutrons, its atomic mass is A + B.
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If Element B Has 9 As The Atomic Number And 19 As The Mass Number What is The Answer how many protons does it have?
B-10 is 10.013
Given : Atomic mass of B = 10.01 amu , % = 19.9 let it be A Atomic mass of B = 11.01 amu , % = 80.1 Solution : A and B are approximately in the ratio 1:4. Isotopic mass = [(proportion of A X at. mass of A) + (proportion of B X at. mass of B)] / 4 = [(1 X 10.01) + (4 X 11.01)] / 4 = (10.01 + 44.04) / 4 = 54.05 / 4 Isotopic atomic mass = 13.512 amu ---- Therefore, isotopic atomic mass of B is = 13.512 amu.
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
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Atomic mass is simply the sum of the number of protons and the number of neutrons. If an atom has "A" protons and "B" neutrons, its atomic mass is A + B.
Atomic mass number of boron(B) - 11
Boron - B - Group IIIThe atomic number is 5.The mass number is 11.
If Element B Has 9 As The Atomic Number And 19 As The Mass Number What is The Answer how many protons does it have?
The atomic mass of Boron (B) is 11 but to be more accurate, the atomic mass is 10.81.
Electron (beta minus) decay: the atomic mass remain approx. constant, the atomic number will be greater with 1 Positron (beta plus) and electron capture decay: the atomic mass remain approx. constant, the atomic number decrease with 1 Double beta decay: the atomic mass remain approx. constant, the atomic number will be greater with 2