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Objectives for higher magnification are usually longer than those for lower magnification ...

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Q: What happens to length of objective when you change from low to high manification?
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Related questions

What happens if you decrease a telescopes eyepiece focal length?

The magnification of the telescope image is(focal length of the objective) divided by (focal length of the eyepiece).The focal length of the objective is fixed.Decreasing the focal length of the eyepiece increases the magnification of the image.(But it also makes the image dimmer.)

What happens to focal length when convex lens is cut horizontally?

no change

Does the numerical aperture of an objective depend on the focal length of the objective?


What would happen if the length of wire increase what happens to frequency?

frequecy will not change

How are the numbers related to the length of the objective?

Because the length of the objectives depends on the total magnification. Example: Magnification: 50x (LPO) You can see that the lower the magnification,the length of objective is the smallest. Magnification: 500x (HPO) You can see that the higher the magnification, the length of objective is bigger than the other objectives. If the objective is lower, the number is lesser -Guinean026

Will the focal length of concave lens change in water?

no, because this happens only in the cases of lenses

How is magnifying power of telescope and a microscope are a affected by increasing the focal length of their objectives?

The magnification of a telescope M is the the focal length of the objective Fo over the focal length of the eyepiece Fe so increasing the focal length of the objective increases the magnification. The magnification of a microscope M is approximately tube length L/Fo x 25/Fe. Therefore increasing the focal length of the objective reduces the magnification.

How do you calculate magnification?

Divide the focal length of the objective lens by the focal length of the eyepiece.

What is more powerful out of the Objective or the Eye piece lens?

The focal length of EyePiece is relatively larger to that of the Objective lens. Power of a lens is inversely proportional to it's focal length. Therefore, Objective is slightly more powerful than EyePiece.

How do I calculate the f stop of a fixed power spotting scope using only the objective lens diameter and the magnification of the device?

We don't think you can do it with that information. 'f-stop' = (focal length of the objective lens) divided by (its diameter) Magnification of the scope = (focal length of the objective) divided by (focal length of the eyepiece) Looks like in order to calculate the 'f-stop', you need to estimate or measure the focal length of either the objective or the eyepiece. Here's an idea: If you can temporarily separate the objective from the tube, use the objective to focus an image of the sun on the sidewalk. (Not on anything flammable.) Measure the distance from the lens to the sharpest image. With the 'object' at infinity, the image is at the focal length.

What happens If a muscle is applied to a load that exceeds the muscle's maximum tension?

The muscle length will not change during a contraction.

Which part are the ocular and objectives connected to?

The telescope tube is between the eyepiece and the objective lenses. It usually consists of two tubes one of which slides inside the other to change the length.