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What does ixxx mean?

Updated: 10/31/2022
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10y ago

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This is not a real roman numeral if that's what you were thinking. You can subtract 1 from 10 but not from 20 or 30 etc. IXXX will link you to porn sites.

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How do you write 08-29-2007 in roman numbers?

08-29-2007 in Roman numerals is written as VIII-XXIX-MMVII.


What is the roman numeral for 3-29-2001?

In todays usage of Roman numerals it is: III-XXIX-MMI But note that the ancient Romans would have worked out the equivalent of 29 as XXVIIII and then abridged them to IXXX thus using less numerals yet retaining their original values.


What is the birthday 29 06 2006 in roman numerals?

The birthday 29 06 2006 in roman numerals is XXIX VI MMVI.


What is the roman number for 29?

Under today's modern rules governing the Roman numeral system 29 is XXIX. However, the Romans themselves wrote out 29 in the form of XXVIIII as can be seen today in the ruins of the Coliseum in Rome and these numerals can be simplified to IXXX (-1+30=29) indeed the Latin word for 29 is 'undetriginta' which literally means one from thirty.


What are the two methods of actually adding together 19 29 and 52 using only Roman numerals?

cAdditional Information:-Under today's rules we would convert 19 and 29 into Roman numerals as XIX and XXIX which makes any form of interaction between other numerals quite difficult.But there is evidence to suggest that the Romans themselves would have actually worked out the equivalent of 19 and 29 as XVIIII and XXVIIII then simplified them to IXX and IXXX which uses less numerals but of equal value thus making addition quicker and simpler as follows:-IXX+IXXX = IIL (20-1)+(30-1) = (50-2)IIL+LII = C (50-2)+52 = 100Alternatively:-XVIIII+XXVIIII = XXXXVIII (19+29 = 48)XXXXVIII+LII = C (48+52 = 100)Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1Remember that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=MQuod Erat Demonstrandum

Related questions

Roman Numerals for 5-29-55?

V-IXXX-DV


What is 3-29-06 in roman numerals?

III-XXVIIII-VI or III-IXXX-VI. Note that 29 in Roman numerals is not XXIX.


How do you write 08-29-2007 in roman numbers?

08-29-2007 in Roman numerals is written as VIII-XXIX-MMVII.


What is 9-29-1999 in Roman Numerals?

Present notation: IX-XXIX-MCMXCIX Previous notation: IX-IXXX-IMM There is evidence that can still be found today that the Romans themselves would have calculated the equivalent of 9-29-1999 on an abacus counting device as VIIII-XXVIIII-MDCCCCLXXXXVIIII which can be simplified to IX-IXXX-IMM. For instance the Latin word for IXXX is 'undetriginta' which literally means one from thirty and the numerals of XXVIIII can be found on one of the entrances of the Coliseum in Rome. Today's rules governing the Roman numeral system were modified during the Middle Ages presumably to make them easier for conversion purposes into Hindu-Arabic numerals and vice versa. The Hindu-Arabic system of numeracy eventually superceded the Roman numeral system because it contained a zero symbol which made calculations much more quicker and efficient.


What is the roman word for 29?

Latin was the language spoken by the Romans and the equivalent words for 29 were 'viginta et novem' for XXVIIII or 'undetriginta' for IXXX Note that in today's modern usage of Roman numerals 29 is now considered to be XXIX and there no Latin word for it.


What is the roman numeral for 3-29-2001?

In todays usage of Roman numerals it is: III-XXIX-MMI But note that the ancient Romans would have worked out the equivalent of 29 as XXVIIII and then abridged them to IXXX thus using less numerals yet retaining their original values.


What is the birthday 29 06 2006 in roman numerals?

The birthday 29 06 2006 in roman numerals is XXIX VI MMVI.


What is the roman number for 29?

Under today's modern rules governing the Roman numeral system 29 is XXIX. However, the Romans themselves wrote out 29 in the form of XXVIIII as can be seen today in the ruins of the Coliseum in Rome and these numerals can be simplified to IXXX (-1+30=29) indeed the Latin word for 29 is 'undetriginta' which literally means one from thirty.


How would you work out 59 plus 29 plus 19 added in two different ways and 59 minus 29 minus 19 subtracted in two different ways but with all work shown in Roman numerals?

The rules as we now know them today governing the Roman numeral system had absolutely nothing to do with the ancient Romans whatsoever because they were introduced during the Middle Ages which was nearly a thousand years after the demise of the Roman Empire and so it's now deemed that 59, 29 and 19 when converted into Roman numerals are LIX, XXIX and XIX respectively which does not lend themselves quite easily towards arithmetical interactivity but notwithstanding the aforementioned inasmuch that it's now possible to glean and extrapolate from credible historical sources including the Latin language itself that the ancient Romans would have in all probability calculated the given numbers as in any of the following formats:-ILX+IXXX+IXX = CVII meaning (-1+60)+(-1+30)+(-1+20) = 107LVIIII+XXVIIII+XVIIII = CVII meaning 59+29+19 = 107ILX-IXXX-IXX = XI meaning (-1+60)-(-1+30)-(-1+20) = 11LVIIII-XXVIIII-XVIIII = XI meaning 59-29 -19 = 11Note that in mathematics that -(-1+30) is -29 and also that the above numerals can be intermingled yet having the same results as for example ILX+IXXX+XVIIII = CVII


What are the two methods of actually adding together 19 29 and 52 using only Roman numerals?

cAdditional Information:-Under today's rules we would convert 19 and 29 into Roman numerals as XIX and XXIX which makes any form of interaction between other numerals quite difficult.But there is evidence to suggest that the Romans themselves would have actually worked out the equivalent of 19 and 29 as XVIIII and XXVIIII then simplified them to IXX and IXXX which uses less numerals but of equal value thus making addition quicker and simpler as follows:-IXX+IXXX = IIL (20-1)+(30-1) = (50-2)IIL+LII = C (50-2)+52 = 100Alternatively:-XVIIII+XXVIIII = XXXXVIII (19+29 = 48)XXXXVIII+LII = C (48+52 = 100)Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1Remember that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=MQuod Erat Demonstrandum


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