They all begin with AUG, which is the start codon.
The sequence of amino acids (forming a protein) that result from the mRNA strand CAG-AAG-UUC-CUC-UCG-C would be: Glutamine-Threonine-Phenylalanine-Leucine-Serine Each codon must be three bases long - therefore the end of this mRNA sequence 'C' cannot code for an amino acid. There would also need to be a stop codon at the end to complete translation.
Because the nucleotide that codes for methionine also is the "start" signal, so whenever a polypeptide starts it uses the exact same code (AUG) so methionine must start every polypeptide chain.
Protine Synthesis is explained below. The answer is in understanding the process itself.This process can be divided into two parts:1. TranscriptionBefore the synthesis of a protein begins, the corresponding RNA molecule is produced by RNA transcription. One strand of the DNA double helix is used as a template by the RNA polymerase to synthesize a messenger RNA (mRNA). This mRNA migrates from the nucleus to the cytoplasm. During this step, mRNA goes through different types of maturation including one called splicingwhen the non-coding sequences are eliminated. The coding mRNA sequence can be described as a unit of three nucleotides called a codon.2. TranslationThe ribosome binds to the mRNA at the start codon (AUG) that is recognized only by the initiator tRNA. The ribosome proceeds to the elongation phase of protein synthesis. During this stage, complexes, composed of an amino acid linked to tRNA, sequentially bind to the appropriate codon in mRNA by forming complementary base pairs with the tRNA anticodon. The ribosome moves from codon to codon along the mRNA. Amino acids are added one by one, translated into polypeptidic sequences dictated by DNA and represented by mRNA. At the end, a release factor binds to the stop codon, terminating translation and releasing the complete polypeptide from the ribosome.One specific amino acid can correspond to more than one codon. The genetic code is said to be degenerate.
The nuclear membrane.In eukaryotic cells, DNA is transcribed into mRNA within the nucleus. Once transcription is complete the mRNA must exit the nucleus to be translated into protein, which ocurrs in the cytoplasm. Thus, mRNA must pass through the nuclear membrane.
The ribosome.
A codon is exactly three bases long, so an mRNA strand with 60 bases would contain 20 codons. The first codon will encode for methionine (this is called the "start" codon) and the last codon will be a "stop" codon, which does not encode for an amino acid. Thus, an mRNA strand of 60 bases will code for 19 amino acids. Keep in mind, it is possible for a stop codon to be anywhere on the mRNA strand, and when a stop codon reaches the ribosome, translation must stop. For example, if an mRNA strand contained 30 codons, and the 15th were a stop codon, the mRNA would only code for 14 amino acids and then be done. The other 15 codons would go untranslated.
AGC needs to be paired up with UCG (which is the specific mRNA codon) in order to transfer message from mRNA to polypeptide. In addition it is a part of process in trancription (for elongation). **Hopefully I have answered this question correctly..if not, please correct it..thanks!
In the cytoplasm, rRNA binds to the "start" codon of a mRNA molecule. Next, a tRNA molecule with the complimentary anticodon binds to the mRNA start codon and releases an amino acid. As the mRNA moves through the rRNA, new tRNA's come along and bind to the mRNA, adding a new amino acid each time. Eventually a "stop" codon is reached, and the rRNA, mRNA, and tRNA break apart, releasing a long chain of amino acids which will fold into a protein.
The sequence of amino acids (forming a protein) that result from the mRNA strand CAG-AAG-UUC-CUC-UCG-C would be: Glutamine-Threonine-Phenylalanine-Leucine-Serine Each codon must be three bases long - therefore the end of this mRNA sequence 'C' cannot code for an amino acid. There would also need to be a stop codon at the end to complete translation.
A codon is a three-base sequence (three nitrogen bases in a row) on mRNA. It calls for a specific amino acid to be brought to the growing polypeptide.An anticodon is a three-base sequence on tRNA. It matches the codon. That's how the right amino acid is put onto the polypeptide next. The tRNA must fit its anticodon onto the mRNA codon like a jigsaw puzzle piece. Each tRNA can only bring one kind of amino acid.
In order to answer this question, you must, and prpbably do have the codon sequences of the RNA or DNA, and a chart saying what each codon codes for in terms of amino acids. The mRNA from transcription is what the sheet probably has on it, with each codon contained therin signaling a certain amino acid. If you can post the sequence or something like that, then ill sertainly answer it for you.
ribosome, where it serves as a template for the assembly of amino acids into a protein chain. This process is facilitated by transfer RNA (tRNA) molecules that bring the appropriate amino acids to the ribosome based on the codons on the mRNA. Once the ribosome reaches a stop codon on the mRNA, protein synthesis is complete.
To determine the amino acid sequence from DNA, one must first transcribe the DNA into mRNA. Then, the mRNA is translated into a sequence of amino acids using the genetic code. Each set of three nucleotides in the mRNA, called a codon, corresponds to a specific amino acid. By reading the codons in the mRNA, one can determine the amino acid sequence.
Because the nucleotide that codes for methionine also is the "start" signal, so whenever a polypeptide starts it uses the exact same code (AUG) so methionine must start every polypeptide chain.
Protine Synthesis is explained below. The answer is in understanding the process itself.This process can be divided into two parts:1. TranscriptionBefore the synthesis of a protein begins, the corresponding RNA molecule is produced by RNA transcription. One strand of the DNA double helix is used as a template by the RNA polymerase to synthesize a messenger RNA (mRNA). This mRNA migrates from the nucleus to the cytoplasm. During this step, mRNA goes through different types of maturation including one called splicingwhen the non-coding sequences are eliminated. The coding mRNA sequence can be described as a unit of three nucleotides called a codon.2. TranslationThe ribosome binds to the mRNA at the start codon (AUG) that is recognized only by the initiator tRNA. The ribosome proceeds to the elongation phase of protein synthesis. During this stage, complexes, composed of an amino acid linked to tRNA, sequentially bind to the appropriate codon in mRNA by forming complementary base pairs with the tRNA anticodon. The ribosome moves from codon to codon along the mRNA. Amino acids are added one by one, translated into polypeptidic sequences dictated by DNA and represented by mRNA. At the end, a release factor binds to the stop codon, terminating translation and releasing the complete polypeptide from the ribosome.One specific amino acid can correspond to more than one codon. The genetic code is said to be degenerate.
Codon-anticodon pairing is crucial in protein synthesis because it ensures that the correct amino acid is added to the growing protein chain. The codon on the mRNA molecule must match with the complementary anticodon on the tRNA molecule to bring the right amino acid. This accurate pairing is essential for the proper sequence of amino acids in the protein, which ultimately determines its structure and function.
The nuclear membrane.In eukaryotic cells, DNA is transcribed into mRNA within the nucleus. Once transcription is complete the mRNA must exit the nucleus to be translated into protein, which ocurrs in the cytoplasm. Thus, mRNA must pass through the nuclear membrane.