1.7x10^-18
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∙ 11y agoA mole of argon includes Avogadro's Number of atoms of argon. Therefore, the answer is (3.0 X 1024)/(6.022 X 1023) or 5.0 moles, to the justified number of significant digits.
Ten million atoms / Avagadro's Number, 6.022e23 atoms per mole = 1.66e-17 moles
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Approx 0.223 moles.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
1,67.1024 argon atoms is equal to 2,773 moles.
A mole of argon includes Avogadro's Number of atoms of argon. Therefore, the answer is (3.0 X 1024)/(6.022 X 1023) or 5.0 moles, to the justified number of significant digits.
Ten million atoms / Avagadro's Number, 6.022e23 atoms per mole = 1.66e-17 moles
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Approx 0.223 moles.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
0.25 moles, approx.
55.64
2.3 × 1024 atoms of Ar
1,638 moles contain 9,864266723766.10e23 atoms.
44 moles of atoms