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At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)

This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.

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Dean Turcotte

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Q: If clock frequency is 5 MHz how much time is required to execute an instruction of 18 T states?
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How many machine cycles and T-series requires to complete the execute STA 4200H in 8085 microprocessor?

The STA 4200H instruction in the 8085 requires 4 machine cycles and 13 T states to complete its fetch, processing, and execution. Cycle One: Opcode fetch, 3 T states plus one opcode process state. Cycle Two: Opcode address byte 00H fetch, 3 T states Cycle Three: Opcode address byte 42H fetch, 3 T states Cycle Four: Accumulator store, 3 T states. Each cycle will have additional T-Ready states as needed by the READY pin. 13 T states is the minimum. The LDA instruction will also require 13 T states, with the last cycle being a read cycle instead of a write cycle.


If the frequency spectrum of a signal has a bandwidth of 500 Hz with the highest frequency at 600 Hz what should be the sampling rate?

The Nyquist Therorem states that the lowest sampling rate has to be equil to or greather than 2 times the highest frequency. Therefore the sampling rate should be 400Hz or more.


What are the disadvantages of the pole placement technique?

The only problem with this technique is that more states are required to be known. These states can be either measured or estimated.


What is sampling thearm cocerning the rate of sampling required for analog signal?

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How many machine cycles do one byte instructions have?

Depending on the particular microprocessor, a machine cycle is the fetch or store of one (typically, one byte) native word. In the 8085, this is a byte fetch or store, plus the overhead in decoding and processing the instruction. In this case, the first machine cycle is four clock cycles, or T states, and subsequent machine cycles are three clock cycles, although certain instruction sequences, such as DAD, require two extra clock cycles.

Related questions

How 8085 timing diagram works based on each instruction?

Each instruction requires specific time for the execution of instruction and this time is called instruction cycle. Each instruction cycle consists 1 to 5 machine cycle -- opcode fetch, memory read, memory write, IO read, IO write and each machine cycle consist 3 to 6 T - states. Time required to execute 1 T-state = 1/ operating frequency of 8085 Microprocessor for example operating frequency = 2MHz then time required to execute 1 T-state = 0.5 uSec example: Calculate time required to execute instruction MOV C, A sol: This instruction has one machine cycle i.e. opcode fetch (In any instruction 1st cycle is always opcode fetch and opcode fetch consists 4 to 6 T state depend on the operation of particular instruction) so to execute MOV C, A required 4T states so time required to execute this instruction is 4*0.5usec = 2usec any other queries pls contect: nileshbahadure2000@yahoo.co.in example:Calculate the time required to execute LXI H,2000H sol:Here we have to draw opcode fetch and two memory reads as two bytes 00H and 20H have to be read from memory. i.e, opcode fetch+Memory reads *2(bytes address) =4+3+3 so to execute LXI H,2000H,the required T-states is 10T and time is 10*0.5usec=5usec


If the frequency of the crystal connected to 8085 is 6MHz calculate the time to fetch and executed NOP instruction?

At a crystal frequency of 6MHz, the 8085 microprocessor has a clock frequency of 3MHz, or a period of 333 nanoseconds. The NOP instruction requires four clock cycles, three to fetch and one to execute, so the NOP instruction with a crystal frequency of 6MHz would take 1.333 microseconds to fetch and execute. This does not include wait states, each of which would add 0.333 microseconds to the timing.


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If the clock frequency is 5 MHz how much time is required to execute an instruction of 18 T states?

At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.


How many machine cycle required for the instance like move a b?

The MOV A,B instruction requires 1 machine cycle and 4 T-states, 3 to fetch the opcode, and 1 to decode/execute it.


What is the fetch-decode-cycle on a computer?

when we execute a program, the starting address is loaded in the program counter. Then for each instruction the processor goes through fetch-decode-execute states. At the fetch state the instruction code is fetched then decoded to understand what exactly has to be done. Then finally it executes that instruction. This process goes on till it reaches the end of the program.


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How many machine cycles are required for RET instruction in 8085 microprocessor is?

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Presidential Oath of Office required to be sworn by every US President."I do solemnly swear (or affirm) that I will faithfully execute the office of presidential of the United States, and will to the best of my ability, preserve, protect, and defend the constitution of the United States"


How many states must consent before Congress can execute most of it's powers?

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