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1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl

Q: How to prepare 1000 ppm chloride solution from sodium chloride?

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200/1000 x 6 = 1.2 moles

how to prepare 1000 ppm solution of nickel carbonate

Dissolve 1,9 g ultrapure, dried potassium chloride in 1L distilled water at 20 oC using a volumetric flask.

take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.

You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below. By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.

Related questions

One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.

Dissolve 3,2788 g Na3PO4 in 1000 mL of this water solution.

200/1000 x 6 = 1.2 moles

Just take 3 grams and add this to 1000 litres (= 1,000 kg = 1,000,000 (million) grams)

use the equation that is standard: 1000 ml 1 M solution= (MOLECULAR WEIGHT) X ml 0.05 M solution = ((MOLECULAR WEIGHT)*X*0.05)/1000

0.9% means there is 0.9 grams NaCl per 100ml of solution. So 1000 ml of 0.9% sodium chloride contains 9.0 grams of NaCl.

how to prepare 1000 ppm solution of nickel carbonate

Dissolve 1,9 g ultrapure, dried potassium chloride in 1L distilled water at 20 oC using a volumetric flask.

Weigh 1.499gm of pure Sodium Nitrite Standard (Purity>99%) in an A class volumetris flask and dissolve completly in double distilled water up to the mark.

What volume of this solution do you desire? Let's say you want to make 1 liter of such a solution. You would weigh out 1 gram (1000 mg) of NaCl and dissolve it in enough water to make a final volume of 1 liter (1000 ml). Since 1000 ppm means 1000 mg/liter, this is how you make 1 liter of that solution. For larger or smaller volumes, adjust appropriately.

Thermal expansion of sodium chloride: - at 75 K: 19.10-4/K - at 273 K: 40. 10-4/K - at 1000 K: 69,5.10-4/K

volume given =27.5mlmolarity of base=0.105find number of moles=moles=vol(cm3)/1000*molarity of NaClmoles=27.5/1000*0.105=3.82 moles of sodium chloride