Normality is equal to molarity if only a single hydrogen is involved, which fortunately it is.
35% HCl contains 350 grams of HCl per 1000 grams (or ml) of water. What is desired is 10 ml of a 6 Normal (or molar) solution. The molecular weight of HCl is 36 grams/mole, so 6 normal would be 216 grams per 1000 mls. This is equivalent to 2.16 grams per 10 milliliters (1000 ml = 1 liter). 35% HCl contains 0.350 grams per ml, so one would need 6.17 ml to give 2.16 grams. The other 3.82 ml will be pure water.
Accordingly you can prepare as much quantity as you require.
I'm not sure about the 37 thing but here is from NIOSH method in how to prepare 6N HCL -pipette 25.64 mL of 11.7 N (37% HCL fuming) to 50 mL volumetric flask and top up with distilled water GOOD LUCK Always add acid to water.
very strong - 6 molar
You cannot make HCL out from just Xhlorine. U will need Hydrogen to. Hcl is a Hydrochloric solution so u will need a method to combine Hydroger and chlorine in order to make HCL
25.0 mL of the 1.00N HCl, diluted up to 100 mL gives you 0.25N
chloramine NH3 + HCl --> NH4Cl (ammonium chloride, son!)
I'm not sure about the 37 thing but here is from NIOSH method in how to prepare 6N HCL -pipette 25.64 mL of 11.7 N (37% HCL fuming) to 50 mL volumetric flask and top up with distilled water GOOD LUCK Always add acid to water.
very strong - 6 molar
6n+5 = 11
-5=6n+7 -5-7=6n+7-7 -12=6n -12/6=6n/6 -2=n
6n-1 = 5
6n-15 = -9
6n-1248 = -1242
You cannot make HCL out from just Xhlorine. U will need Hydrogen to. Hcl is a Hydrochloric solution so u will need a method to combine Hydroger and chlorine in order to make HCL
5n + 6n - 2n
6n + 5n is 11n.
6n/10=3 6n=30 n=5
6n+3=15 6n+3-3=15-3=12 6n = 12 n=12/6 = 2