The formula you are looking for is W = A x V.
real P= V * I *cos(phase angle between V and I)for purely resistive loads or DC voltages this equals real power P=V*I = 120*5= 600Wattsfor not pure resistive loads you'd have to measure the phase angle between Voltage and Current to get real power.However, at home, the utility company charges for Complex power = V*I.So you'd still pay for V*I.
the simplest solution is by connecting two 120v 3amps heater in series , the same can be used directly on 240v. However the current drawn will still be 3 amps & Not 1.5 amps. The heater output power will be double that of a single heater running on 120v. ( or equvalent to two heaters operating on 120v. supply ) A more expensive method is to use a stepdown transformer which can be powered on 240v & connect the heater on the transformer 120v side. this method will consume approx. 1.5 amps from the 240v supply.
One can find a 120V electric power cable in stores such as Lowe's or Home Depot. It can also be purchased online through the store websites or through sites like rakuten for a cheaper price.
No. The neon sign is fed by a step-up transformer. Primary side 120V, secondary side 7500V. If you applied 240 to the primary side you would get 15000 volts on the neon tube. A flash over and then nothing. If you can find a transformer from 120V to 240V or 240V to 120V then you are good to go. Connect 240V to 240V side and you will get 120V out the other, connect the 120V side to the neon sign and you should have light. Transformer should be at least 100va. This will give you an output of .83 amps at 120V
Power is measured in Watts, power (Watts) = E (volts) x I (current - amps) current is determined by the internal resistance (R) of the lightbulb, the lower the resistance the more current will flow. 120v x 0.5a = 60W 120V x 0.83a = 100W the 100W lightbulb will draw more current We also have Ohm's law: E(volts) = I (amps) x R (ohms) Household voltage stays the same at 120v we have for a 100w lamp: 120v = I x R R = 120v/0.83 amps R = 144.6 ohms for a 60w lamp: 120v = I x R R = 120v/0.5 amps R = 240 ohms The higher watt lamp has lower resistance.
1440 Watts
Power is multiplication of voltage and current. You need to know the load current drawing to establish the power. It is a bad idea to use 230 v adapter in 120 volts outlet
You can find a 120V power cable at your local hardware store. Look in the section under extension cords.
120v
real P= V * I *cos(phase angle between V and I)for purely resistive loads or DC voltages this equals real power P=V*I = 120*5= 600Wattsfor not pure resistive loads you'd have to measure the phase angle between Voltage and Current to get real power.However, at home, the utility company charges for Complex power = V*I.So you'd still pay for V*I.
You can use 120v 10a 125w cable projectors 110-240v power in India.
I'll assume you mean 150 Watts in which case it isn't that much power. It would depend on the circuit from which you are drawing this power to ultimately determine if it is "a lot of power". A typical house in the US has 120V circuits with 15-20A breakers which would allow the circuit to handle a load of 1,800-2,400 Watts.
there is 120V across the circuit.
the simplest solution is by connecting two 120v 3amps heater in series , the same can be used directly on 240v. However the current drawn will still be 3 amps & Not 1.5 amps. The heater output power will be double that of a single heater running on 120v. ( or equvalent to two heaters operating on 120v. supply ) A more expensive method is to use a stepdown transformer which can be powered on 240v & connect the heater on the transformer 120v side. this method will consume approx. 1.5 amps from the 240v supply.
The APC 1500 has a standard power of 865 watts/1500 VA. The APC 1500 has an output of 120V and an output of 120v. The specifics of the model can be found on the official website.
there is 120V across the circuit.
yes