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How many total moles of KNO3 must be dissolved in water to make 1.5 liters of a 2.0 M current?
Wiki User
∙ 8y ago
8 moles of KCl are needed.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoThe answer is 3 moles KNO3.
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What is the total number of moles of solute in 2.0 liters of 3.0 M NaOH?
I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
What is the molarity of a solution that contains 4.9 moles of MgCl in a total volume of 4.3 liters?
Molarity, i.e. molar is moles per litre. You need to keep the same proportion but bring the volume to a litre. So in other words, 4.9 moles in 4.3 litres is 4.9/4.3 moles per litre, i.e. 1.14 molar.
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
What is the molarity of a solution with 0.207 mol of calcium acetate dissolved in a total volume of 166.5mL?
Molarity = moles solute/liters solution = 0.207 moles/0.1665 L = 1.24 molar (3 sig. figs.)
What is the total number of moles of solute in 2.0 liters of 3.0 M NaOH?
I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How do you calculate the molarity of the solution of 17.52 grams of Na Cl in a total volume of 2000 ml of solution?
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
What is the molarity of a solution that contains 4.9 moles of MgCl in a total volume of 4.3 liters?
Molarity, i.e. molar is moles per litre. You need to keep the same proportion but bring the volume to a litre. So in other words, 4.9 moles in 4.3 litres is 4.9/4.3 moles per litre, i.e. 1.14 molar.
What are three ways you can measure concentration?
The three main ways are: molarity (M) = moles solute/liters solution; molality (m) = moles solute/kilograms solvent; mole fraction = moles 1 component/total moles all components. There's also percent by volume, percent by mass, and normality.
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
750 ml of 20M HCl is mixed with 250 ml of 60M HCl What is the new molarity?
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
The partial pressure of F2 in a mixture of gases where the total pressure is 1atm is 300 torr what is the mole fraction of F2?
0.395 total moles moles F 760.torr 300.torr total moles moles F 2 2 = ×
What is the total number of moles of nacl formed with 2 moles of na2cro4 react completely?
4 moles
What is the total number of atoms in 3.5 moles of calcium?
The total number of atoms in 3.5 moles of calcium is 21,0774929995.10e23.
