add 2.4ml glacial aetic acid in one liter of d.m water
The answer is 20,15 mL.
This depends on your experiment.
Vinegar is an example for an aqueous solution of acetic acid.
(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)
An acetic acid solution has no color and a unique odor.
The answer is 20,15 mL.
This depends on your experiment.
To prepare a 0.1 N glacial acetic acid solution, calculate the required mass by multiplying 0.1 moles by the molar mass of glacial acetic acid (60.05 g/mol). Weigh out the calculated mass and add it to a clean container. Dissolve the glacial acetic acid completely by stirring it with distilled water. Transfer the solution to a 1-liter volumetric flask and dilute it to the 1-liter mark with distilled water. Mix thoroughly, label, and store the solution properly, taking necessary safety precautions when handling glacial acetic acid.
Dehydration of acetic acid to prepare acetic anhydride occur at 8oo oC.
Vinegar is an example for an aqueous solution of acetic acid.
Vinegar is a weak solution of acetic acid.
Iodine monochloride is soluble in alcohol, ether, acetic acid. ICl is prepared from iodine and chlorine.
(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)
Vinegar is a dilute solution of acetic acid and is created by diluting concentrated acetic acid 20 fold to create a 5% acid solution.
An acetic acid solution has no color and a unique odor.
Take 100 gm acetic acid. With 99% purity,it contains 99 gm of Acetic Acid. To make 5% solution,add 1880 gms water.
That is the condensed formula for the weak acid acetic acid.CH3COOH is a common formula for acetic acid written by biochemists and biologists