Without going into a long derivation, the diameter (D) of a particle (in microns) can be estimated from a material with a known surface area (SA, in m2/gram) and density (p, in gram/cm3) using the equation D = 6 / (SA * p). As an example, an aluminum powder with a surace area equal to 0.5 m2/gram and a density of 2.7 gram/cm3 would be 4.44 microns (D = 6/(0.5*2.7) = 6/1.35 = 4.44) Assumptions: You are assuming that you have equi-sized, spherical particles (which is never the case, but allows for a good approximation).
A triangle is a flat area, therefore it has a surface area, not a volume. Density is unrelated to the problem; you would need some additional information to calculate the surface area.
You cannot use surface area to calculate density. Density is a calculation comparing TOTAL area and weight of an object. In short you must use the total volume of the object when calculating the density.
You cannot These are different concepts. you need a volume and density to calculate mass, surface area provides neither (a cube and a sphere with the same surface area have different volumes and, had they been made of the same material, would have different masses).
mass divided by volume asses mass divided by volume asses
For the amount of material in the particle the surface area of a small particle is greater than a larger particle. Said another way, the surface area per unit volume is greater for a smaller particle. Dissolving speed is related to the surface area. Therefore a smaller particle dissolves faster than a larger particle.
to calculate the area of the front surface of a box you should
You need to:* Calculate the surface area * Calculate the volume * Divide the surface area by the volume
surface area divided by volume
To calculate the surface area of a shape find the area of each side, and then, add all of the areas together. The sum of the areas is the surface area.
You measure or calculate the surface area; you measure or calculate the volume and then you divide the first by the second. The surface areas and volumes will, obviously, depend on the shape.
The total surface area increases.
It depends on the shape whose surface area you are interested in.