what is the balanced equation for Rubidium metal reacting with halogen iodine
2Al + 3I2 -> 2AlI3
Yes. Rubidium is an alkali metal in the sodium group. It will react with iodine to form rubidium iodide:- 2Rb+ I2 -> 2RbI
The rubidium iodide is RbI.
Iodine
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
Rubidium metal would react with iodine to make rubidium iodide , according to the equation: 2 Ru + I2 -> 2 RuI
2Al + 3I2 -> 2AlI3
Yes. Rubidium is an alkali metal in the sodium group. It will react with iodine to form rubidium iodide:- 2Rb+ I2 -> 2RbI
The rubidium iodide is RbI.
kelage a tu? mercoir
Iodine
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
2Cs (s) + I2 (l) = 2CsI (s)
Balanced:H2 + I2 ----> 2 HI
Rubidium iodine
It does so in 1:3 ratio; hence the formula AlI3.Aluminum iodine is another example of iodine
The word equation for the reaction of rubidium with water is rubidium + water --> rubidium hydroxide + hydrogen. Rubidium is a metal that reacts very quickly and fiercely, even explosively with water.