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A sample of helium has a volume of 325mL and a pressure of 655mm Hg what will be the pressure if the helium you compressed to 125mL?
Wiki User
∙ 13y ago
P1V1=P2V2
VI=325ml P1=655mm Hg
V2=125ml P2=?
=655 x 325= P2 x 125
=(655 x 325)/ 125
=212875/125
=1703mm Hg. :)
Wiki User
∙ 13y ago
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A sample of helium gas has a volume of 900 milliliters and pressure of 2.50 ATM at 298k what is the new pressure when the temoerature is changed to 336 k and the volume is decreased to 450 milliliters?
5.64 ATM
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Because the helium is compressed.Because that small tank is extreAmly compressed with helium. So it has a LOT of helium in it. It can just fit into the small tank because it's highly compressed.
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To solve for the original pressure of the helium gas, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. Using this law, we can set up the equation (P1)(V1) = (P2)(V2), where P1 is the original pressure, V1 is the original volume, P2 is the final pressure, and V2 is the final volume. Plugging in the values gives us (P1)(200 mL) = (300 mm Hg)(0.240 mL). Solving for P1 gives us P1 = (300 mm Hg)(0.240 mL) / 200 mL = 0.36 mm Hg. Therefore, the original pressure of the helium gas was 0.36 mm Hg.
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