I think this would be a problem of momentum. p=mv so if the momentum of the bullet is 20 (.01x200=20) then the recoil velocity should equal 10 m/sec (2x10=20). Good old Newtons 3rd Law.
Sir Isaac Newton's 3rd Law of Motion states that for every action, there is an equal and opposite reaction. A firearm propels a bullet towards a target, the mass (~weight) of the bullet and its acceleration create a force in the opposite direction of the bullet's travel. You can play around with the bullet's mass (~weight) and its velocity to get equal recoil: 1- bullet 20grams, accelerates at 100m/s has the same recoil as: 2- bullet 200grams, accelerating at 10m/s (recoil force = 2000 for both)
When you fire a rifle,the recoil kick is introducing you to Newton's Third Law.If you you don't hold the rifle properly to absorb the recoil in your whole body, the recoil will leave a nasty bruise mark; (mv) recoil = (mv) bullet. You want to minimize the recoil velocity by maximizing the recoil mass=your rifle + your body. Getting the [proper stance and grip will raise the recoil mass the reduce the impact on your body.
When a gun is fired a bullet (or cartridge) with a small mass but a very high velocity is ejected. The recoil of the gun is a reaction to this force and is sufficient to push back the person who fired the weapon.
There is a Reaction, called recall or kick. That should read "recoil."
the conversion of momentum law states that the total momentum of twos systems must be equal therefore M1V1 = M2V2 i am assuming the mass of the bullet is 0.0050 kg and not 50kg so (0.0050 * 250) = ( 9 * X) X = (1.25 / 9) X = 0.139 You can't answer these kind of questions with so few parameters. The bullet diameter, barrel length, powder burn rate all greatly effect the answer. The recoil is caused mainly by the gas exiting the barrel, hence muzzle brakes work.
muzzle velocity is the velocity of bullet and recoil velocity is the velocity of gun.
Sir Isaac Newton's 3rd Law of Motion states that for every action, there is an equal and opposite reaction. A firearm propels a bullet towards a target, the mass (~weight) of the bullet and its acceleration create a force in the opposite direction of the bullet's travel. You can play around with the bullet's mass (~weight) and its velocity to get equal recoil: 1- bullet 20grams, accelerates at 100m/s has the same recoil as: 2- bullet 200grams, accelerating at 10m/s (recoil force = 2000 for both)
Newton said "For every action, there is an equal and opposite reaction." The action is pushing the bullet in one direction. Reaction is the gun being pushed in the other. The energy is speed times mass. The gun masses much more than the bullet, and so will move proportionately slower than the bullet. Which is a very good thing- or the recoil of the gun would kill the shooter.
because the recoil is when the bullet forces the gun back and so the bullet creates the recoil and so it can't make it go just as fast
The forward velocity of the bullet is greater than the recoil velocity of the rifle because of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. When the bullet is fired forward with high velocity, the rifle experiences a recoil in the opposite direction but with lower velocity due to the mass difference between the bullet and the rifle.
.351 km/hr
When you fire a rifle,the recoil kick is introducing you to Newton's Third Law.If you you don't hold the rifle properly to absorb the recoil in your whole body, the recoil will leave a nasty bruise mark; (mv) recoil = (mv) bullet. You want to minimize the recoil velocity by maximizing the recoil mass=your rifle + your body. Getting the [proper stance and grip will raise the recoil mass the reduce the impact on your body.
light
Bullet forward, gun back - as in when the gun is fired, the bullet goes forward, and the explosion pushes (recoil) the gun backwards.
Whether you need it depends on the specific situation, but the recoil velocity does affect the total energy.
Momentum before = momentum after. Since there was no movement before, momentum before = 0 If you think of the bullet as forward/positive momentum and the gun as backward/negative momentum then the momentum of the bullet plus the momentum of the gun =0 and therefore the momentum of the bullet = the momentum if the gun. momentum = mass x velocity P=m/v 20gx150m/s = 2000g (2kg) x velocity 3000 = 2000v 3000 / 2000 = v v = 1.5m/s
Use conservation of linear momentum. Before firing the bullet the total momentum was zero (assuming you were not moving), therefore, after firing the bullet, the total momentum must needs also be zero. Therefore, after the shot, m1v1 + m2v2 = 0, where m1 and v1 correspond to the pistol, and m2 and v2 correspond to the bullet.