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I think this would be a problem of momentum. p=mv so if the momentum of the bullet is 20 (.01x200=20) then the recoil velocity should equal 10 m/sec (2x10=20). Good old Newtons 3rd Law.

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Q: A rifle of mass 2 kg is suspended by strings the rifle fires a bullet of mass 0.01 kg at a speed of 200 ms the recoil velocity of the rifle is what?
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What is recoil of a gun?

Sir Isaac Newton's 3rd Law of Motion states that for every action, there is an equal and opposite reaction. A firearm propels a bullet towards a target, the mass (~weight) of the bullet and its acceleration create a force in the opposite direction of the bullet's travel. You can play around with the bullet's mass (~weight) and its velocity to get equal recoil: 1- bullet 20grams, accelerates at 100m/s has the same recoil as: 2- bullet 200grams, accelerating at 10m/s (recoil force = 2000 for both)


How does a rifle demonstrate Newton's third law of motion?

When you fire a rifle,the recoil kick is introducing you to Newton's Third Law.If you you don't hold the rifle properly to absorb the recoil in your whole body, the recoil will leave a nasty bruise mark; (mv) recoil = (mv) bullet. You want to minimize the recoil velocity by maximizing the recoil mass=your rifle + your body. Getting the [proper stance and grip will raise the recoil mass the reduce the impact on your body.


Why does the gun recoils and puch the person back when fired?

When a gun is fired a bullet (or cartridge) with a small mass but a very high velocity is ejected. The recoil of the gun is a reaction to this force and is sufficient to push back the person who fired the weapon.


When bullet penetrates into the target what happens?

There is a Reaction, called recall or kick. That should read "recoil."


A bullet with a mass of 0050kg is fired from a gun of a mass 9kg the bullet has a velocity of 250ms What is the velocity with which the gun recoils?

the conversion of momentum law states that the total momentum of twos systems must be equal therefore M1V1 = M2V2 i am assuming the mass of the bullet is 0.0050 kg and not 50kg so (0.0050 * 250) = ( 9 * X) X = (1.25 / 9) X = 0.139 You can't answer these kind of questions with so few parameters. The bullet diameter, barrel length, powder burn rate all greatly effect the answer. The recoil is caused mainly by the gas exiting the barrel, hence muzzle brakes work.

Related questions

What is the Difference between muzzle velocity and recoil velocity?

muzzle velocity is the velocity of bullet and recoil velocity is the velocity of gun.


What is recoil of a gun?

Sir Isaac Newton's 3rd Law of Motion states that for every action, there is an equal and opposite reaction. A firearm propels a bullet towards a target, the mass (~weight) of the bullet and its acceleration create a force in the opposite direction of the bullet's travel. You can play around with the bullet's mass (~weight) and its velocity to get equal recoil: 1- bullet 20grams, accelerates at 100m/s has the same recoil as: 2- bullet 200grams, accelerating at 10m/s (recoil force = 2000 for both)


How the velocity of recoil of a gun fire is 1'100 times the velocity of bullet if mass of a gun is 100 times of mass of bullet?

Newton said "For every action, there is an equal and opposite reaction." The action is pushing the bullet in one direction. Reaction is the gun being pushed in the other. The energy is speed times mass. The gun masses much more than the bullet, and so will move proportionately slower than the bullet. Which is a very good thing- or the recoil of the gun would kill the shooter.


Why does a gun not recoil just as fast as the speed of the bullet?

because the recoil is when the bullet forces the gun back and so the bullet creates the recoil and so it can't make it go just as fast


A rifle is fired and you are able to measure both the muzzle velocity of the bullet as well as the recoil velocity of rifle how do you explain the fact that the forward velocity of the bullet is great?

The forward velocity of the bullet is greater than the recoil velocity of the rifle because of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. When the bullet is fired forward with high velocity, the rifle experiences a recoil in the opposite direction but with lower velocity due to the mass difference between the bullet and the rifle.


Bullet with mass 60.0 g is fired with an initial velocity of 575 ms from a gun with mass 4.50 kg The speed of the recoil of the gun you?

.351 km/hr


How does a rifle demonstrate Newton's third law of motion?

When you fire a rifle,the recoil kick is introducing you to Newton's Third Law.If you you don't hold the rifle properly to absorb the recoil in your whole body, the recoil will leave a nasty bruise mark; (mv) recoil = (mv) bullet. You want to minimize the recoil velocity by maximizing the recoil mass=your rifle + your body. Getting the [proper stance and grip will raise the recoil mass the reduce the impact on your body.


Which will give a lesser recoil on a pistol..an ammunition with a heavier bullet or a lighter bullet?

light


What is the term recoil o f the gun?

Bullet forward, gun back - as in when the gun is fired, the bullet goes forward, and the explosion pushes (recoil) the gun backwards.


Does recoil velocity answer involve in the calculation of final kinetic energy?

Whether you need it depends on the specific situation, but the recoil velocity does affect the total energy.


What is the recoil velocity of the pistol when a bullet of mass 20g is fired with a velocity 150ms from a pistol of mass 2kg?

Momentum before = momentum after. Since there was no movement before, momentum before = 0 If you think of the bullet as forward/positive momentum and the gun as backward/negative momentum then the momentum of the bullet plus the momentum of the gun =0 and therefore the momentum of the bullet = the momentum if the gun. momentum = mass x velocity P=m/v 20gx150m/s = 2000g (2kg) x velocity 3000 = 2000v 3000 / 2000 = v v = 1.5m/s


What is the recoil velocity of the pistol when a bullet of mass 200g is fired with a velocity 30m per second from a pistol of mass 100kg?

Use conservation of linear momentum. Before firing the bullet the total momentum was zero (assuming you were not moving), therefore, after firing the bullet, the total momentum must needs also be zero. Therefore, after the shot, m1v1 + m2v2 = 0, where m1 and v1 correspond to the pistol, and m2 and v2 correspond to the bullet.