A well designed circuit should be able to operate over a range of voltages, not just at one voltage. Especially a circuit which is intended to be powered by a battery. As the battery starts to get used up, and the voltage drops, you want the circuit to operate as planned.
When the voltage supplied to a circuit remains constant and the circuit's resistance decreases, the current drawn from the source must increase.
Quite simply, the current would fall.
This question follows Ohm's law which states, "Current is directly proportional to the applied EMF (voltage) and inversely proportional to the current in the circuit. <<>> decreased
It is halved. coz voltage=current * resistance
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
Voltage drop due to the resistance present in the series circuit causes voltage split over a series circuit.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
If you are referring to a simple circuit, you could add resistance throughout it. Increased resistance means decreased current flow yet the same voltage.
If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.
No, the resistance in a circuit does not change when voltage changes. Resistance is an inherent property of the circuit.
This question follows Ohm's law which states, "Current is directly proportional to the applied EMF (voltage) and inversely proportional to the current in the circuit. <<>> decreased
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
To increase (current) flow in a circuit you increase voltage (or decrease resistance). Ohm's Law: Current = Voltage divided by resistance
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
It is halved. coz voltage=current * resistance