5% in pure water
it depends on what you are trying to irrigate and what the solvent is.
yes
hyper
If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass of initial solution must be diluted to 50 times its original mass to obtain the desired lower concentration, or in other words, 49 parts of diluent must be mixed with each part of initial solution. If the percents involve volume measurements, it would be necessary to take into account and change in density occasioned by the dilution.
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
what is the composition of dextrose 5%
8.0 g according to my teacher but i dont know the formula
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
90 ml of dextrose and 4.41 litres of water.
it depends on what you are trying to irrigate and what the solvent is.
25
50 ml
This solution is used for the hydration of the organism and also for the equilbration of sodium in blood.
143
28
Hypertonic dextrose solution
D5W or Dextrose 5% in an IV bag is clear. There should be no discoloration. If you break open the bag and feel the solution it is sticky and runs like thin syrup.