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If your Winchester model 1912 pump action shotgun,which was made in the year 1914 is a standard model model 12 shotgun with no cutts compensator attched to the barrel and has a original finish of between 60%-90%.Then you may expect to get between 275-475 dollars.

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Q: What is value of Winchester Model1912 12ga Serial 54748 pump shotgun?
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How do you create a cell to type in any numbers to test for Armstrong Numbers up to 6 digits and a corresponding cell to automatically display yes or no?

Armstrong numbers are the sum of their own digits to the power of the number of digits. Here are all the possible Armstrong Numbers up to six digits:1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748, 92727, 93084, 548834EXAMPLE: 153 = 13 + 53 + 33Sometimes, the simple solutions are better than complicated elegant solutions. Just compare your number to the list. If your number is on the list, it is an Armstrong Number.Designing a spreadsheet formula to compare all numbers 1-6 digits to determine if they are one of twenty possible numbers does not make sence. However, in the spirit of education (even though using this solution does not pass the common sense test), here are two methods you can use to solve this problem.SOLUTION #1 (easy): Compare against a look-up table.=IF(ISERROR(VLOOKUP(A1,C1:C20,1,FALSE)),"No","Yes")Reserve A1 for entry of the number to be evaulated.In B1, enter this formula: =IF(ISERROR(VLOOKUP(A1,C1:C20,1,FALSE)),"No","Yes")In column C (C1:C20), enter the first twenty Armstrong Numbers [see list above].Enter a number in A1 and observe "Yes" or "No" in B1.SOLUTION #2 (difficult): Brute force calculation.=IF(LEN(F1)=6,IF(MID(F1,1,1)^6+MID(F1,2,1)^6+MID(F1,3,1)^6+MID(F1,4,1)^6+MID(F1,5,1)^6+MID(F1,6,1)^6=F1,"Yes","No"),"Not 6 places")Here is an example for 6-digit numbers (use the same procedure for other size numbers or write a macro that will count the characters and loop through as many times as necessary):Reserve A1 for entry of the number to be evaulated.In B1, enter this formula: =IF(LEN(F1)=6,IF(MID(F1,1,1)^6+MID(F1,2,1)^6+MID(F1,3,1)^6+MID(F1,4,1)^6+MID(F1,5,1)^6+MID(F1,6,1)^6=F1,"Yes","No"),"Not 6 places")In B1, observe "Yes" or "No" (if you have not entered a 6-digit number, you will see "Not 6 places.")


Write a c program to find Armstrong number using ifstatement?

#include<stdio.h> int main(){ int num,r,sum,temp; int min,max; printf("Enter the minimum range: "); scanf("%d",&min); printf("Enter the maximum range: "); scanf("%d",&max); printf("Armstrong numbers in given range are: "); for(num=min;num<=max;num++){ temp=num; sum = 0; while(temp!=0){ r=temp%10; temp=temp/10; sum=sum+(r*r*r); } if(sum==num) printf("%d ",num); } return 0; }