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What is the pH of 0.15 M NaOH?

Updated: 8/11/2023
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9y ago

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pH 1 to 2.

Sulfuric acid is a strong diprotic acid: [H+] = 2* 0.15 = 0.30 mole/L H+

pH = -log 0.30 = 0.52

pH 2.

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13y ago
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9y ago

To calculate the pH, first what you do is find pOH by using the equation pOH= -log[OH] --> pOH= -log[.15M] = .8239. Next, we know that pH+pOH=14. So to find the pH we subtract .8239 which we found earlier from 14--> 14-.8239 = 13.176. So, pH of .15M NaOH= 13.18 (rounded)

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12y ago

0.30102999566398

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Q: What is the pH of 0.15 M NaOH?
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