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The result of a 40 newton force acting on one direction and a 50 newton force acting in the opposite direction would be a net force of 10 newtons, acting in the same direction as the 50 newton force.

If both forces act in an opposite direction you would take one and subtract from the other.

-50N i 40N i = -10N i you would add their magnitude and get a resultant of 5N. If they were added in acting in the same direction you'd have a resultant of 90N. If they were acting at angles with each other you would have to break them into x, y, and z components, add the x components with the x, y with the y, and z with the z, then take all the new values, square them all, add them, and take the root which would give you your new magnitude.

(x,y,z) + (x',y',z') = (x+x', y+y', z+z') (for the new vector)

the new magnitude would be

Sqrt((x+x')^2+(y+y')^2+(z+z')^2)

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10y ago
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14y ago

The answer is 10 N to the right. Because these are opposing forces, we can simply add them as vectors. Because they are vectors in opposing directions, we subtract the magnitude of one vector from another, as in 40 - 30.

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14y ago

That depends on the angle between the two forces.

The net can be anything from 10 newtons (if they act in exactly opposite directions),

up to 90 newtons (if they act in exactly the same direction).

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10y ago

Since the two forces are moving in the same direction, you can just add the two forces together and get 90 N in whatever direction the forces are going.

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13y ago

the net force will be 10N to the right

this is because the force to the right is greater by 10N

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15y ago

the net force is 30 N to the right.

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14y ago

Net force ON the box is 10N to the right.

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Q: What is the net force produced by a 40 newton force and a 50 newton force if the forces act in opposite directions?
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Continue Learning about Physics

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