2^64-1 = 18446744073709551615
/* hanoi.c */ #include <stdio.h> #include <stdlib.h> static long step; static void Hanoi (int n, int from, int to,int spare) { if (n>1) Hanoi (n-1,from,spare,to); printf ("Step %ld: move #%d %d-->%d\n", ++step, n, from, to); if (n>1) Hanoi (n-1,spare,to,from); } int main (int argc, char **argv) { int n; if (argc==1 (n= atoi(argv[1]))<=0) n= 5; step= 0; Hanoi (n, 1, 2, 3); return 0; }
This algorithm reads the value of number of discs and prints the move that are to be done for playing towers of hanoi.Pre: n is a positive integer which carries the value of number of discs.Post: prints the moves that are to be done for transferring discs in ascending order in another peg1.initialize value of n(positive integer greater than 1)2.moves = pow(2,disk)-13.if(n=1)i) moves disk from "from" to "to"4. end if5. elsei)hanoi(n-1,from,aux,to)ii) moves disc from "from" to "to''iii) hanoi(n-i,from,aux,to)6.end else7. prints the movesend towers_of_hanoi
When the wall moves away from the backfill, the earth pressure on the wall decreases. This minimum pressure is called active earth pressure. On the other hand if the wall moves towards the backfill, the earth pressure increases. This maximum pressure is called passive earth pressure.
due to reflecting torque pointer moves in one direction by due to controlling torque pointer moves in opposite direction therefore pointer oscillate in forward and backward direction.if there is no deflecting torque the device to ensure that the pointer comes to rest quickly with minimum oscillation at its correct reading position is known as damping device...
The traditional bubble sort moves any number of elements at most one position per iteration, while selection sort moves exactly one element per iteration. Both sorts require an exponential amount of time to produce their results.
The number of moves required to solve the Hanoi tower is 2m + 1 . Therefore for a tower of five disks the minimum number of moves required is: 31.
The number of moves required to solve the Hanoi tower is 2m + 1 . Therefore for a tower of five disks the minimum number of moves required is: 31.
127
100000000
1,048,575 moves and I know because I did the math.
To move n disks, you need 2n-1moves. In this case, 31.
If there are N discs, the minimum number of moves required is 2N - 1.
#include#includevoid hanoi(int x, char from,char to,char aux){if(x==1){printf("Move Disk From %c to %c\n",from,to);}else{hanoi(x-1,from,aux,to);printf("Move Disk From %c to %c\n",from,to);hanoi(x-1,aux,to,from);}}int main(void){int disk;clrscr();printf("Enter the number of disks you want to play with:");scanf("%d",&disk);double moves=pow(2,disk)-1;printf("\nThe No of moves required is=%g \n",moves);hanoi(disk,'A','C','B');getch();}
For any n-disc version of the Tower of Hanoi, the optimum solution for the puzzle takes a minimum of 2n-1 moves. In the case of 6, 7, 8-sized Towers of Hanoi, the puzzle would take: 26-1 = 63, 27-1 = 127, 28-1 = 255 moves.
There is a formula for calculating the number of moves. The formula is 2^n-1. This means that to move one disk the number of moves can be calculated as 2^1-1. For two disks the calculation is 2^2-1. Using this formula the answer 1023 can be found
If you love puzzles, mathematics, or computer programming then the "Tower of Hanoi" problem is brain teaser designed just for you. At first glance, the Tower of Hanoi problem appears to be a simple matter of trial and error. The problem consists of three wooden pegs. The center wooden peg contains 8 discs of varying size. The discs decrease in diameter from the bottom to top. For example, the bottom disc could be 8 inches in diameter and the disc on top of it could be 7 inches in diameter, continuing to the 8th disk, a 1 inch disc on the very top. At the beginning of the problem, the two remaining pegs do not contain any discs. The goal of the Towers of Hanoi problem is to move all the discs from the center peg to one outside peg. Sounds easy, right? There are two rules that you must follow. Rule #1 is that you can move only one disc at a time. Rule #2 is that you can not place a larger disc on top of a smaller disc. This is the reason why there are three pegs in the problem as opposed to just two pegs. The puzzle may be based on an Indian legend (Towers of Brahma) where (someplace in antiquity) there is a room with three posts having 64 disks. Brahmin priests are tasked with moving the disks from one post to another. When the task is done, the world will end. Based on moving the disks at one disk per second, this would take about 585 billion years. (18,446,744,073,709,551,615 moves) Other variations of the legend exist. --- The minimum number of moves for three pegs and n disks = (2^n) - 1, so for 8 disks, the number of moves should be 255. The first 3 moves are A1, B3, A3, followed by C1, A2, B1, A1.
In the Challenge Mode, if you solve a puzzle using the minimum amount of moves, you will earn a 3 star rating and be rewarded with another hint. Have fun!