53.9 % Al
46.1 % O
if there is no mass of the compound, we can use Atomic Mass unit to replace it and assume the total is over 100.
base on Periodic Table, we can see Al= 26.9815 and O=15.9994 so we multiple Al with 2 and O with 3
then Al=53.963 and O=47.9982, total up Al and O equal to 101.9612 and we get 101.9612.
to get the percentage of Al,we need to divide Al over total up both of them, 53.963/101.9612 X 100 = 52.925% and O, 47.9982/101.9612 X 100 = 47.075%
Molar mass of AlPO3:
Al = 1 * 26.98 g = 26.98 g
P = 1 * 30.97 g = 30.97 g
O = 3 * 16.00 g = 48.00 g
Total = 105.95 g
% O by mass = grams O/grams AlPO3 * 100%
48.00 g/105.95 g * 100% = 45.30%
The percent of oxygen by mass in aluminum phosphite is about 45.3%.
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.
In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.
GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3
UNKNOWN: % Al3+
EQUATION:
% Al3+...=...g Al3+x 100...g Al2O3
% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
Aluminium makes up 52.925%; oxygen accounts for 47.075%.
The molas mass of aluminium oxide is 2x27 + 3x16 = 102 g/mol.
O x 3.
haha losers i answered this question and i am 12! u guys should know this if i do. wow.
Sulfur: 49, 986 12 %
Oxygen: 50,013 88 %
101.96
The formula of potassium iodide is KI, showing that each formula unit contains one atom of each constituent element. The gram atomic mass of potassium is 39.0983 and that of iodine is 126.904. Therefore, the percentage by mass of iodine in the compound is 100[126.904/(126.904 + 39.0983) or 76.4471 %, to the justified number of significant digits.
The chemical formula of the compound. This shows the composition directly in atomic ratios, which can be converted to mass ratios by using the atomic weights of each element in the compound.
You find the weights of each element in the compound and divide by their relative atomic mass to find out the moles. You find the simplest ratio of the mole values you have found and then you can find the percentages using this ratio
To work this out you need the formula of the compound and your periodic table to tell you the relative atomic masses of each element. First add up all the relative atomic masses to get the relative formula mass. Then for each element in turn, take its relative atomic mass (multiplying up if there is more than one of it in the formula) and divide by the relative formula mass, then multiply by 100 to get a percentage. I'm not going to give you the answer - partly because then you'll never practise doing it for yourself, and partly because I wonder if you meant magnesium permanaganate, or the more usual school compound of potassium permanganate, KMnO4.
The percentage is 23,14 %.
Mass percentage calculations determine the percentage of an element based on mass in a compound. This can then be used to determine the percentage in a compound of each individual element.
the percentage by mass of each element in a compound.
The percent composition of a compound tells the amount of each element in the compound as a percentage. It is possible to find if the mass of an element and the total mass of the compound is known.
Yes, because the mass of each element in a compound depends on the mass of the compound.
Percentage composition= (mass of the element/mass of the molecule)*100 The fraction of the molecule's mass that comes from the element's mass
Do the atomic mass of each element/ compound which makes up air divided by 100 and then times by the percentage that the element exists in air. This should give you the mass that each element/ compound contributes to the atomic mass of air. Add them all together to get the overall atomic mass of air. (I calculated this and it came out at 25.6 3sf )
This is the percent chemical composition.
yes
empirical formaula
mass of the solute/(mass of solution + mass of the solute) x 100%ie: if 67.1g of CaCl2 is added to 275g of water, calculate the mass percent of CaCl2 in the solution.67.1/342.1=.1961.1961 x 100% = 19.6% of CaCl2
The percent of Chlorine in the compound SnCl4 is 54.434% along with an atomic mass of 35.453. The percentage is the equivalent of the mass percent of this element.
The number of atoms of one element in the compound