Its length is 12 cm because 2(12+10) = 44 cm
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
Let the length be x+5 and the width be x:- Perimeter = 2*(x+5+x) or 4x+10
The formula to find the perimeter of a rectangle is: P = 2L + 2W, where 2L is the length multiplied by 2 and 2W is the width multiplied by 2. Hence: P = 2*10 + 2*5 P = 20 + 10 P = 30
rectangle with 10" length and 2x-4 width 60" area
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
The length is 20 units and the width is 10 units
One rectangle that has a perimeter of 30 has a length of 5 and a width of 10.
length + width = 20/2 = 10 length = 7cm, width = 3cm
The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.
I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.
2 sides have length 10 and the other 2 sides have width 8 perimeter is sum of sides = 10+10+8+8 = 36
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
multiple the length by 2 then subtract that from the perimeter. then divide that by two. for example length=10 perimeter=30 ... 30-2(10)= 30-20=10 10/2=5 width=5
10 inches
20r + 10
15 feet