P(dBm) = 10log10(10mW) = 10dBm
Thermal fade margin TFM in db is the difference between the normal received signal RSL at the input of microwave receiver expressed in dbm and the receiver's threshold ( given by the manufacturer) expressed in dbm TFM = RSL - TH
WE CAN use the balanced modulator & also the double balanced modulator(DBM) THANKS. ASMA
Thermal fade margin TFM in db is the difference between the normal received signal RSL at the input of microwave receiver expressed in dbm and the receiver's threshold ( given by the manufacturer) expressed in dbm TFM = RSL - TH
Here's how to convert dB units (with usually a 1 Watt or whatever 1 value as reference) to dBm units (with a 1 miliWatt reference value):x= value to be convertedx [dB]= x + 30 [dBm]Proof:P= 1 Watt--> 10*log10(1)= 0 [dB] (this is 1 Watt in dB)--> 10*log10(1/(1*10^(-3)))= 10*log(1*10^3)= 30 dBm (this is 1 Watt to dBm)Now, if you do whatever number of examples you want to do, you'll end up in concluding the conversion dB to dBm is totally linear without of actually having to proof the linear properties. (i'm too lazy to write it here).Hope this helps....Regards,STMI
20 dbm
Yes, DBM (data base management) is real.
dBw=dBm-30 then 75-30=45 dBw dBw=dBm-30 then 75-30=45 dBw dBw=dBm-30 then 75-30=45 dBw
DBM outplacement information can be located directly on the DBM website. You can also locate this type of information on career transition websites as well.
dBm us almost exactly the same as dB. The only difference is that there is a reference of 1 Watt = 0 dB, and 1 mW = 0 dBm. Sorry but that is incorrect. db is a ratio and not an absolute value, by it self it means nothing. you got the dbm part right, 1 mW = 0 dbm and it is an absolute value.
Mic level is -56 to -40 dbm. Line level is either -10 dbm or 4 dbm. You need a preamp to amplify a microphone to line level.
Gain = Pout - Pin = -10dBm - (-5dBm) = -5dB
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.