The weak nuclear force is responsible for all particle decay. In a neutron, there are two down (d) and one up (u) quars with charges of -1/3 and +2/3, respectively. In a proton, there are two up and one down quark. The configuation looks like this:
N: udd
P: uud
One of the down quarks in the neutron changes into an up quark (via the W- particle) and an electron. The neutron is now a proton.
Strong Nuclear Force is responsible for both Alpha and Fission decay.
Weak Nuclear Force is responsible for Beta decay.
Alpha particles consist of 2 protons & 2 neutrons. These particles, then, have charge +2
alpha: mass 4, charge +2beta: mass ~1/1800, charge -1gamma: mass 0, charge 0
gamma decay beta decay alpha decay
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The only possible product of the alpha decay of 92238U is 90234Th.
Tritium, 13H, cannot decay by alpha decay because it only has one proton, and an alpha particle has two protons, along with its two neutrons. The lightest nuclide capable of alpha decay is lithium-5, 35Li, decaying by alpha decay to ordinary hydrogen, 11H. 13H decays by beta- decay to 23He, a rare form of helium, which is then stable.
Beta particles, from beta- decay, have a charge of -1. Beta particles, from beta+ decay, have a charge of +1. Alpha particles have a charge of +2.
alpha: mass 4, charge +2beta: mass ~1/1800, charge -1gamma: mass 0, charge 0
gamma decay beta decay alpha decay
No. Decay is the process, radiation is the product.
It's called alpha-decay. The two protons and two neutrons are removed in the form of alpha particles, or helium nuclei.
92Au 282Xe +13S
It is alpha decay. In the process, an alpha particle(He2+) is released. So, it is called alpha decay.
I'm pretty sure its alpha.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
The only possible product of the alpha decay of 92238U is 90234Th.
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.