There is no single value that this equals. There could be any number of answers to it depending on the value of x.
If you want to know what x equals when a specific value is assigned to the equation, you can do this by solving the equation for a 0 value, and then factoring the result.
For example, let's say you you want to know the value of x when the equation equals negative four:
x2 + 8x + 12 = -4
∴ x2 + 8x + 16 = 0
∴ (x + 4)2 = 0
Now you simply plug in the value on the left side of the equation that would give you a result of 0. In this case, it would be negative four, as negative 4 plus 4 equals 0, which is also 0 when squared.
∴ x = -4
Similarly, if you say that the equation comes to a value of 5:
x2 + 8x + 12 = 5
∴ x2 + 8x +7 = 0
∴ (x + 7)(x + 1) = 0
In this case, there are two possible outcomes: negative 7 and negative 1. That's because either one of those will produce a zero value for this equation.
∴ x = -7 or x = -1
Alternately, what happens if the equation comes to a value of 1?
x2 + 8x + 12 = 1
∴x2 + 8x + 11 = 0
In this case, there is no simple way to solve it by factoring, so instead you can plug it into the quadratic formula, x = [-b +/- √(b2 - 4ac)] / 2a
∴ x = [-8 +/- √(82 - 4×1×11)] / (2×1)
∴ x = [-8 +/- √(64 - 44)] / 2
∴ x = (-8 +/- √20) / 2
∴ x = -4+√20, or -4-√20
∴ x ≈ 0.47214, or x ≈ -8.42714
As shown, there can be any number of correct answers to this, as there is no specified value for x. Once a value is specified, then it will always have at most two answers, and at least one.
no
x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
In general, no.
x2 + 8x + 12 = (x + 6) (x + 2)
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
x2-8x+12 = 0 (x-2)(x-6) = 0 x = -2 or x = -6
x=-0.7
2x^2 + 8x + 3 = 0
x2 + 8x - 6 = 0 x2 + 8x + 16 = 22 (x + 4)2 = 22 x + 4 = ± √22 x = -4 ± √22