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STD in non medical terms can be Short Term Disability; therefore it looks like you are covered with STD and possibly LTD as well. Check with your HR department.
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What does STD devs stand for?
standard deviations
What does std on a paycheck stand for?
Short Term Disabilty
In religion what does STD stand for?
Doctor of Sacred Theology
What does FBO stand for on wiring money?
for the benefit of
Why can't free trade exist without restrictions?
Because elected officials stand to benefit too much from special interests who stand to benefit from the limited and hindered competition that trade restrictions produce.
What is mening of STD ISD?
Given this question is in the Technology section, I'm going to assume it's technology based... They are telecommunication based abbreviations which stand for...STD: Subscriber Trunk Dialling.ISD: International Subscriber Dialling.
What does the sexual acronym SD stand for?
It stands for Sexual Disease. Normally, you will see STD which stands for Sexually Transmitted Disease.
What does fxstd stand for on a Harley Davidson?
The FX represents the style of front end on the bike. The STD is Soft Tail Deuce.
Which US politicians stand to benefit from not prosecuting illegal online gambling?
Obama.
How do you use sin in c plus plus?
#include<iostream> int main() { std::cout << "sin(1) = " << std::sin(1.0) << std::endl; std::cout << "cos(1) = " << std::cos(1.0) << std::endl; std::cout << "tan(1) = " << std::tan(1.0) << std::endl; std::cout << "asin(1) = " << std::asin(1.0) << std::endl; std::cout << "acos(1) = " << std::acos(1.0) << std::endl; std::cout << "atan(1) = " << std::atan(1.0) << std::endl; } Output: sin(1) = 0.841471 cos(1) = 0.540302 tan(1) = 1.55741 asin(1) = 1.5708 acos(1) = 0 atan(1) = 0.785398
How do you split a string in delimit c plus plus?
#include<iostream> #include<vector> #include<string> std::vector<std::string> parse (const std::string& s, const char delim) { std::vector<std::string> result {}; auto start = 0U; auto end = s.find (delim); while (end != s.npos) { result.push_back (s.substr(start, end - start)); start = ++end; end = s.find (delim, start); } result.push_back (s.substr (start, s.npos - start)); return result; } std::vector<std::string> parse (const std::string& s, const std::string& delim) { std::vector<std::string> result {}; auto start = 0U; auto end = s.find (delim); while (end != s.npos) { result.push_back (s.substr(start, end - start)); start = end + delim.length(); end = s.find (delim, start); } result.push_back (s.substr (start, s.npos - start)); return result; } int main() { std::string str1 = "This is a string that will be parsed by a single-space delimiter."; std::string str2 = "This==is==a==string==that==will==be==parsed==by==equal==operator."; std::string str3 = "This string has no delimiter."; std::cout << str1 << std::endl; std::vector<std::string> v1 = parse (str1, ' '); for (auto i : v1 ) std::cout << i << std::endl; std::cout << std::endl; std::cout << str2 << std::endl; std::vector<std::string> v2 = parse (str2, "=="); for (auto i : v2 ) std::cout << i << std::endl; std::cout << std::endl; std::cout << str3 << std::endl; std::vector<std::string> v3 = parse (str3, '\\'); for (auto i : v3 ) std::cout << i << std::endl; std::cout << std::endl; }
Swapping of two nos using pointer in c plus plus?
There is no benefit in swapping two numbers using a pointer. It's actually quicker to swap the two numbers themselves. However the following shows how to swap values by changing the pointers to those value. #include <iostream> int main() { int X = 5; int Y = 6; // Point to the values in X and Y. int *pX = &X; int *pY = &Y; // Print current values and the values being pointed at: std::cout << "Before swapping:" << std::endl; std::cout << " X = " << X << ", Y = " << Y << std::endl; std::cout << "pX = " << *pX << ", pY = " << *pY << std::endl; // Swap the pointers. pX = &Y; pY = &X; // Print current values and the values being pointed at: std::cout << "After swapping:" << std::endl; std::cout << " X = " << X << ", Y = " << Y << std::endl; std::cout << "pX = " << *pX << ", pY = " << *pY << std::endl; return( 0 ); }
