The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
The buoyant force is zero when the object is just touching the liquid. As the object displaces more volume, the buoyant force increases until the object is completely submerged. Once the object is submerged, it doesn't matter how deep it is, the buoyant force remains constant.
They are equal.
I think you mean a buoyant force. When an object is submerged into a liquid, the liquid pushes up on the object with a force equal to the weight of the amount of fluid that is displaced.
The buoyant force is equal to the amount of water displaced. Multiply the volume of the object by the density of water - then convert that to a force (at about 9.8 newton/kilogram).
No.
The buoyant force is zero when the object is just touching the liquid. As the object displaces more volume, the buoyant force increases until the object is completely submerged. Once the object is submerged, it doesn't matter how deep it is, the buoyant force remains constant.
The greater the pressure against the bottom of a submerged object produces an upward buoyant force
buoyant force
If the weight of the object is higher than the buoyant force the object SINKS. And the opposite happens if the weight is lower than the buoyant force. If it is equal, the object neither sink nor float, it is neutrally buoyant.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
FALSE
FALSE
The buoyant force on a fully submerged object is equal to the weight of the water displaced. In fact, that's also true of a floating object.
No.
i will float
it is archimedes' principle
On its volume.