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Count them: FF(16)=255(10)=11111111(2)

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Q: The minimum number of bits required to store the hexadecimal number FF is?
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What is The minimum number of bits required to store the hexadecimal number FF?

Eight.


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The number of digits required to store a number in binary is substantially greater than that required in octal and even larger than in hex.


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Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.


WRITE A Program to convert integar to hexadecimal in c language?

Use the %X modifier of printf.Code Example:#include int main(void) { unsigned int iMyNumber = 255; printf("The number %u interpreted as hexadecimal is %X.\n", iMyNumber, iMyNumber); return 0; }


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