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The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24.

The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).

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Q: The length of the rectangle is greater than its breadth by 2 cm if the length is increased by 4 cm and the breadth decreased by 3cm the area remain same find the length and breadth of the rectangle?
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Related questions

Can length of rectangle be greater than its breadth always?

Usually, yes.


The perimeter of the rectangle is 60cm what is the length of the rectangle?

Assuming that the length of a rectangle is greater than its breadth, any value L such that 15 ≤ L < 30 cm will do. Then breadth, B = 30 - L cm.


If a rectangle has perimeter of 1.57 kilomteres its length is 168 meters what is breadth?

Perimeter = 2*(Length + Breadth) So, 1570 = 2*(168 + Breadth) 785 = 168 + Breadth Breadth = 617 metres Which is rather an unusual result because normally the length is greater than the breadth.


Is the value of a number less than 1 and greater 0 increased or decreased by raising it to any power and the value of a number greater than 1?

any no. between 0&1 when raised to some power will obviously decreased.


The length of a rectangle is 7 feet more than width if the length were decreased by 3 feet and the width were increased by 2 feet the perimeter would be 32 feet what is the length of the original re?

twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).


IS it compulsory that length always greater than breadth?

No, but language implies it.


Will a rectangle with a greater perimeter also have a greater areea?

Yes.


Ten times a number increased by 5 is greater than twelve times a number decreased by one?

10x + 5 > 12x - 2 7 > 2x 7/2 > x


Can a rectangle have a greater perimeter and also have a greater area?

Of course, a rectangle can have a greater perimeter and a greater area. Simply double all the sides: the perimeter is doubled and the area is quadrupled - both bigger than they were.


What are the dimension of a rectangle with 60 square units?

The area of a rectangle does not provide enough information. Let L be any number greater than sqrt(60) = approx 7.75 and let B = 60/L. Then a rectangle with length L units and Breadth B units will have an area of L*B = L*(60/L) = 60 square units. Since L can be any number greater than 7.75, there are infiitely many choices for L and so infinitely many possible rectangles.


What is the minimum perimeter of the rectangle?

The way the rectangle is usually defined, a rectangle has to be positive, so any number greater than zero will do. Note that the set of numbers greater than zero has no minimum.


Can a rectangle have a greater perimeter than another one but have a greater area too?

yes it can; a rectangle 5 by 2 has perimeter 14 and area 10 for example; a rectangle 10 by 2 has perimeter 24 and area 20, both greater.