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The area of a triangle with two sides equal to 1 foot and the angle between those two sides equal to 45 degrees is 0.354 square feet.

Draw a triangle, one side of length 1, from the origin to the right along the x axis. The second side, also of length 1, goes up and to the right from the origin at an angle of 45 degrees with respect to the x axis. The third side connects the two end points of those line, but the length of that line does not matter.

Draw a fourth line from the top of the triangle straight down to the x axis. That is the height of the triangle, and it is also sine(45 degrees), which is one half the square root of two or 0.707. Take the base (1), multiply by the height (0.707) and divide by 2 and you get 0.354.

Technically, the fourth line is sine(45 degrees) divided by the hypotenuse, but since the hypotenuse is 1 (the second line), it was omitted in the prior paragraph for clarity.

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Q: Suppose you have an isosceles triangle and each of the equal sides has a length of foot Suppose the angle formed by those two sides is 45 degrees what is the area?
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