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Isosceles triangle has a base of 12 and a height of 8. What is the length of the legs?
Wiki User
∙ 15y ago
Pythagorean theorem. a^2 + b^2 = c^2. Base divide by 2 = 6 which is the base for each of half of this triangle. Thus 6^2 + 8^2 = c^2. C= 10. The Length of each of the two legs is 10.
Wiki User
∙ 15y ago
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What is the vertical height of a triangle with an area of 48cm2 and a base length of 6cm?
assuming its an isosceles triangle, then its 16 cm high
How can you find the length of the 2 sides of an isosceles triangle when you know the base and the height?
By using Pythagoras' theorem.
Isosceles triangle has a base of 22 and a height of 60 What is the length of the legs?
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3y - 3
Height of an isosceles triangle?
If you know the length of the sides, you can use Pythagoras' Theorem to calculate the height. Use half the base for one of the shorter sides, and either of the two identical sides of the triangle for the hypothenuse. Solve for the other one of the shorter sides (the height).
If the base of an isosceles triangle is 11 and the perimeter is 39 what is the length of a leg?
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
How do you find height of isosceles triangle if you only know the length of equal sides and the base?
i can
How do you find the base and height of an isosceles triangle?
An isosceles triangle has 2 equal base angles and its height is perpendicular from its apex to the centre of its base
Isosceles triangle has a base of 12 and a leg length of 8. What is the height?
square root of 28
What is the vertical height of a triangle with an area of 48cm2 and a base length of 6cm?
assuming its an isosceles triangle, then its 16 cm high
How can you find the length of the 2 sides of an isosceles triangle when you know the base and the height?
By using Pythagoras' theorem.
What is the area of an isosceles triangle with a height of 5 feet and a base measuring 4 feet?
The area of any triangle is (1/2) times (length of base) times (height). We think you can probably handle it from there.
What is The sum of any 2 sides of an isosceles triangle?
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
The triangle at the right is an isosceles triangle. if?
legs Base and height are equal in langth
How do you find the base of an isosceles triangle if the legs are 5 and the area 12?
Area of a triangle = 1/2*base*height 12 = 1/2*base*height 24 = base*height. Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. By trial and improvement lets take the base of the triangle as 6 and its height as 4 An isosceles triangle contains two right angle triangles which in this case they have a base of 3, a height of 4 and a hypotenuse of 5 Using Pythagoras' theorem: 32+42 = 52 From the above information we can deduce that the base of the isosceles triangle is 6 units in length.
How do you find the area of an isosceles tringle?
To find the area of any triangle... divide the length of the base by 2... then multiply the result by the height.
How do find the area of an isosceles tringle?
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
