Yes. The midsection is equal to the average of the two bases.
It is the average of the bases.
Yes
It is 20 units.
It is (7 + 15)/2 = 11 units of length.
A trapezoid midsegment is parallel to the set of parallel lines in a trapezoid and is equal to the average of the lengths of the bases
It is the average of the bases.
No, the length of the midsegment of a trapezoid is equal to the average of the lengths of the bases. The sum of the lengths of the bases would typically yield a longer length than the midsegment.
Yes
It is 20 units.
It is (7 + 15)/2 = 11 units of length.
A trapezoid midsegment is parallel to the set of parallel lines in a trapezoid and is equal to the average of the lengths of the bases
The Trapezoid midsegment conjecture- the midsegment of a trapezoid is parallel to the bases and is equal to the length to the average of the lengths of the bases. This is Some what Algebra....... what you do is take your length 90 and midsegment 85 into a prob like this (90+X)/2=85 times by two on both sides to cancel out the two. after that you end up with 90+X=85 next you have to "isolate" the X by subtracting 90 from both sides you would get 90+X=85 -90 -90 to get X= -5 the other side would be -5 so it doesnt work to check it plug the number back into the equation (90+-5)/2=85
The average of the bases of a trapezoid is the median.
If it is the line joining the midpoints of the parallel sides it most certainly is not.
No its parallel bases can never be equal in length. But if it is in the form of an isosceles trapezoid then its slanted sides are equal in length.
Yes but the parallel bases are of different lengths
The answer depends on what characteristic of how many trapezoids you want to average. The length, perimeter, diagonals, parallel sides (bases), transverse sides, ...