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Probability = number_of_ways_of_success / total_number_if_outcomes

As a cube has 6 faces and you have only specified that it has five numbers (1-5), one of those numbers must be repeated, thus the probability of rolling a 5 depends upon whether there is one or two sides bearing a 5:

If there is only 1 side bearing a 5, then it is 1/6

If there are 2 sides bearing a 5, then it is 2/6 = 1/3

If you meant a five sided solid, then there is no such regular solid and some face(s) would be biased to appear and it would depend upon which face has the 5.

However, an icosahedron has 20 faces and the numbers 1-5 could be repeated 4 times each, meaning that the probability of rolling a 5 would be 4/20 = 1/5.

If you had a regular pentagonal spinner, with each digit corresponding to an edge, then the probability of spinning a 5 would be 1/5.

If you mean a standard die: a cube with six sides numbers 1-6 (and the 1-5 was a typographical error), then the probability is 1/6.

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Q: If you roll a 1-5 number cube what is the probability you will get a 5?
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