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120 V x 0.75 A = 90 watts

2 minutes = 120 seconds

90 watts for 2 minutes = (90) x (120) = 10,800 watt-seconds = 10,800 joules

The motor consumes 10,800 joules of electrical energy during that 2 minutes.

If the motor is perfectly (100%) efficient, then that's the amount of work you

can get out of it.

In the general case, the amouunt of work the motor can do is (10,800 joules) x the motor's efficiency.

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Q: How much work can be done by an electric motor that is plugged into a wall of 120V if 0.75 amps of current flow through it for 2 minutes?
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