4800 watts because watts = volts x amps.
4800✅
An electric clothes dryer demands 22A from a 240V outlet at approximately 90% Power Factor. The power demand on the outlet should be about 240V x 22A x 0.9 = 4.75 kW. The active components in an electric clothes dryer are the heating element (100% PF) and the electric motor that turns the tumbler (70-80% PF). The formula you are looking for is W = I x E. (W is watts, I is current in amps, E is volts)
watts = volts X amps, so: 15A X 240V = 3600 watts
1.7amp
We know that Voltage = Current x Resistance, so if E = I x R, then E = 20 x 12 = 240 volts, and the dryer must be plugged into a 240 volt outlet.
Yes. It draws less current.
The formula you are looking for is W = I x E.
By Ohm's Law Voltage = Current x Resistance R = V / I = 120 / 12 = 10 Ohms
Power (Watts) = Current (Amps) * VoltagePower = 22Amps * 240 VoltsPower = 5,280 Watts5280
11.5 x 240 = 2760W motor.
P=VI so I=P/V I= 60/230 I=0.261 A
Ohm's Law says Voltage = Current x Resistance V = 5 x 24 = 120 V.
Assume the supply as DC (Only resistance given) Voltage drop = 10X10X0.12 = 12V (approx)